Q 1 :    

A monochromatic light of wavelength 6000  is incident on the single slit of width 0.01 mm. If the diffraction pattern is formed at the focus of the convex lens of focal length 20 cm, the linear width of the central maximum is          [2024]

  • 60 mm

     

  • 24 mm

     

  • 120 mm

     

  • 12 mm

     

(B)         Angular width=2λa

              Linear width=2λa·f

                                      =2×6000×10-10×20×10-20.01×10-3

                                       =24×10-3m=24mm

 



Q 2 :    

A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit will be              [2024]

  • 30°

     

  • 15°

     

  • 60°

     

  • 45°

     

(C)      d sinθ=λ(Half angular speed)

           sinθ=λd=2×10-24×10-2=12θ=30°

           Full angular speed=2θ=60°

 



Q 3 :    

A parallel beam of monochromatic light of wavelength 600 nm passes through a single slit of 0.4 mm width. Angular divergence corresponding to the second order minima would be ____ × 10-3 rad.                           [2024]



(6)        sinθθ2λb

            =2×600×10-94×10-4=3×10-3rad

            Total divergence = (3+3)×10-3=6×10-3rad

 



Q 4 :    

A parallel beam of monochromatic light of wavelength 5000 is incident normally on a single narrow slit of width 0.001 mm. The light is focused by a convex lens on the screen, placed on its focal plane. The first minima will be formed for the angle of diffraction of ____ (degree).             [2024]



(30)         For first minima

               asinθ=λ

               sinθ=λa=5000×10-101×10-6=12

                θ=30°

 



Q 5 :    

The diffraction pattern of a light of wavelength 400 nm diffracting from a slit of width 0.2 mm is focused on the focal plane of a convex lens of focal length 100 cm. The width of the 1st secondary maxima will be                        [2024]

  • 2 mm

     

  • 2 cm

     

  • 0.02 mm

     

  • 0.2 mm

     

(1)

width of secondary maxima=λfa

=400×10-9×10.2×10-3=2×10-710-4=2×10-3 m=2 mm

 



Q 6 :    

In a single slit experiment, a parallel beam of green light of wavelength 550 nm passes through a slit of width 0.20 nm. The transmitted light is collected on a screen 100 cm away. The distance of first order minima from the central maximum will be x×10-5m. The value of x is _____.         [2024]



(275)

λ=550 nm

D=100 cm

a=0.20 mm

y=Dλa=100×10-2×550×10-90.2×10-3=275



Q 7 :    

In a single slit diffraction pattern, a light of wavelength 6000Å is used. The distance between the first and third minima in the diffraction pattern is found to be 3 mm when the screen is placed 50 cm away from the slits. The width of the slit is ____×10-4m.           [2024]



(2)

For nth minima bsinθ=nλ

(λ is small so sinθ is small, hence b tanθ = nλ)

btanθ=nλ

byD=nλ

yn=nλDb (Position of nth minima)

B1st minima, A3rd minima

y3=3λDb,  y1=λDb

Δy=y3-y1=2λDb

3×10-3=2×6000×10-10×0.5b

b=2×6000×10-10×0.53×10-3=2×10-4 m

x=2