Q 1 :

In a coil, the current changes from -2A to +2A in 0.2 s and induces an emf 0.1 V. The self-inductance of the coil is:               [2024]

  • 4 mH

     

  • 5 mH

     

  • 2.5 mH

     

  • 1 MH

     

(2)     

           (Emf)induced=-Ldidt

           In magnitude form,

           |Emfind|=|(-)Ldidt|

           ⇒0.1=(L)[+2-(-2)]0.2⇒L=0.1×0.24=5mH

 



Q 2 :

The current in an inductor is given by I=(3t+8) where t is in second. The magnitude of induced emf produced in the inductor is 12 mV. The self-inductance of the inductor ________ mH.                 [2024]



(4)      |∈|=Ldidt

          i=|3t+8|⇒didt=3

          ε=12mV

          |ε|=L|dIdt|⇒12=L×3

          L=4mH

 



Q 3 :

Two coils have mutual inductance 0.002H. The current changes in the first coil according to the relation i=i0sinωt, where i0=5A and ω=50π rad/s. The maximum value of emf in the second coil is πα V. The value of α is _____.                              [2024]



(2)     ϕ=Mi=Mi0sinωt

         EMF=-Mdidt=-0.002(i0ωcosωt)

         EMFmax=i0ω(0.002)=(5)(50π)(0.002)

         EMFmax=π2V



Q 4 :

Two conducting circular loops A and B are placed in the same plane with their centres coinciding as shown in figure. The mutual inductance between them is           [2024]

  • μ0πb22a

     

  • μ0πa22b

     

  • μ02π·b2a

     

  • μ02π·a2b

     

(2)

Magnetic flux through smaller loop, ϕ=Mi=BA

ϕ=(μ0i2b)·πa2=Mi

M=μ0πa22b



Q 5 :

A small square loop of wire of side L is placed inside a large square loop of wire of side L(L=l2). The loops are coplanar and their centers coincide. The value of the mutual inductance of the system is x×10-7H, where x= ____.                  [2024]



(128)

Flux linkage for inner loop.

ϕ=Bcenter·l2=4×μ0i4πL2(sin45+sin45)l2

ϕ=22μ0iπLl2

M=ϕi=22μ0l2πL=22μ0π

=224ππ×10-7=128×10-7 H

⇒x=128



Q 6 :

Regarding self-inductance:

A. The self-inductance of the coil depends on its geometry.

B. Self-inductance does not depend on the permeability of the medium.

C. Self-induced e.m.f. opposes any change in the current in a circuit.

D. Self-inductance is electromagnetic analogue of mass in mechanics.

E. Work needs to be done against self-induced e.m.f. in establishing the current.

Choose the correct answer from the options given below:          [2025]

  • A, B, C, D only

     

  • A, C, D, E only

     

  • A, B, C, E only

     

  • B, C, D, E only

     

(2)

Self-inductance of coil

L=μ0μrN22πR



Q 7 :

Consider I1 and I2 are the currents flowing simultaneously in two nearby coils 1 and 2, respectively. If L1 = self-inductance of coil 1, M12 = mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be          [2025]

  • ε1=–L1dI1dt+M12dI2dt

     

  • ε1=–L1dI1dt–M12dI1dt

     

  • ε1=–L1dI1dt–M12dI2dt

     

  • ε1=–L1dI2dt–M12dI1dt

     

(3)

ϕ1=L1I1+M12I2

ε1=–dϕ1dt=–L1dI1dt–M12dI2dt

Magnitude of induced emf due to self-inductance, =LdI1dt

Magnitude of induced emf due to mutual inductance, =MdI2dt



Q 8 :

Find the mutual inductance in the arrangement, when a small circular loop of wire of radius 'R' is placed inside a large square loop of wire of side L (L>>R). The loops are coplanar and their centres coincide.                  [2023]

  • M=2μ0R2L

     

  • M=22μ0RL2

     

  • M=22μ0R2L

     

  • M=2μ0RL2

     

(3)

ϕ=Mi  also  ϕ=BA

ϕ=πR2(4μ04πi(L/2)2)

⇒  M=22 μ0R2L



Q 9 :

A 12 V battery connected to a coil of resistance 6 Ω through a switch, drives a constant current in the circuit. The switch is opened in 1 ms. The emf induced across the coil is 20 V. The inductance of the coil is                     [2023]

  • 5 mH

     

  • 12 mH

     

  • 8 mH

     

  • 10 mH

     

(4)

Induced emf=-LdIdt

⇒  20=-L(0-2)10-3

⇒  L=10 mH



Q 10 :

Two concentric circular coils with radii 1 cm and 1000 cm, and number of turns 10 and 200 respectively, are placed coaxially with centers coinciding. The mutual inductance of this arrangement will be _________ ×10-8 H. (Take, π2=10)                   [2023]



(4)

r1=1 cm,  N1=10

r2=1000 cm,  N2=200

ϕ1,2=MI2

N2B→2·N1A→1=MI2

⇒  N1N2μ0I22r2·πr12=MI2

⇒  M=10×200×4π×10-7×π×(0.01)22×10

⇒  M=4×10-8



Q 11 :

Three identical coils C1, C2 and C3 are closely placed such that they share a common axis. C2 is exactly midway. C1 carries current I in anti-clockwise direction while C3 carries current I in clockwise direction. An induced current flows through C2 will be in clockwise direction when            [2026]

  • C1 moves towards C2 and C3 moves away from C2

     

  • C1 moves away from C2 and C3 moves towards C2

     

  • C1 and C3 move with equal speeds towards C2

     

  • C1 and C3 move with equal speeds away from C2

     

(1)

Magnetic field through the coil is

B→=(Bc2-Bc1) i^

ϕ=(Bc2-Bc1)A

ε=-dϕdt

Find the direction according to Lenz's law.

If the coil moves away, then the magnetic field decreases and vice versa.

Correct Ans. (1)



Q 12 :

Match List – I with List – II

  List I   List II
A) AC generator I) Detects the presence of current in the circuit
B) Galvanometer II) Converts mechanical energy into electrical energy
C) Transformer III) Works on the principle of mutual induction in AC circuits
D) Zener Diode IV) Voltage regulator

 

Choose the correct answer from the options given below:

  • A – II, B – I, C – IV, D – III

     

  • A – II, B – I, C – III, D – IV

     

  • A – III, B – IV, C – II, D – I

     

  • A – III, B – I, C – II, D – IV

     

(2)

Zener diode is used as voltage regulator.