Q 1 :    

In a coil, the current changes from -2A to +2A in 0.2 s and induces an emf 0.1 V. The self-inductance of the coil is:               [2024]

  • 4 mH

     

  • 5 mH

     

  • 2.5 mH

     

  • 1 MH

     

(B)      (Emf)induced=-Ldidt

           In magnitude form,

           |Emfind|=|(-)Ldidt|

           0.1=(L)[+2-(-2)]0.2L=0.1×0.24=5mH

 



Q 2 :    

The current in an inductor is given by I=(3t+8) where t is in second. The magnitude of induced emf produced in the inductor is 12 mV. The self-inductance of the inductor ________ mH.                 [2024]



(4)      ||=Ldidt

          i=|3t+8|didt=3

          ε=12mV

          |ε|=L|dIdt|12=L×3

          L=4mH

 



Q 3 :    

Two coils have mutual inductance 0.002H. The current changes in the first coil according to the relation i=i0sinωt, where i0=5A and ω=50π rad/s. The maximum value of emf in the second coil is πα V. The value of α is _____.                              [2024]



(2)     ϕ=Mi=Mi0sinωt

         EMF=-Mdidt=-0.002(i0ωcosωt)

         EMFmax=i0ω(0.002)=(5)(50π)(0.002)

         EMFmax=π2V