Q 21 :    

Three magnets A, B and C were dipped one by one in a heap of iron filings. It shows the amount of the iron filling sticking to them:

The strength of these magnets will be:

  • A>B>C

     

  • A < B < C

     

  • A=B=C

     

  • A < B > C

     

(1)



Q 22 :    

If we place the magnetic compass near the north pole of the magnet, which pole of the needle will point towards it?

  • North pole

     

  • South pole

     

  • Keep deflecting

     

  • None of these

     

(2)

As like poles repel each other and unlike poles attract each other. Therefore, when the North pole of a bar magnet is brought near the compass, it gets deflected in the south direction.

 



Q 23 :    

In the circuit shown below, what is direction of the current?

  • No current flowing

     

  • Anti-clock wise

     

  • Clock wise

     

  • Data insufficient

     

(3)

If the current flows from North to South the compass needle will move towards the last.

 



Q 24 :    

A proton enters a magnetic field at right angle to it, as shown below. The direction of force acting on the proton will be:

  • To the right

     

  • To the left

     

  • Out of the page

     

  • Into the page

     

(4)

The proton enters a magnetic field at right-angle to it. Therefore, it will experience a force and the direction of force is calculated using Fleming’s Left-Hand Rule.

 



Q 25 :    

A bar magnet is immersed in a heap of iron fillings and pulled out. The amount of iron filling clinging to the:

  • North pole is almost equal to the South pole

     

  • North pole is much more than the South Pole

     

  • North pole is almost less equal than the South pole

     

  • Magnet will be same all along its length

     

(1)

As the maximum intensity of magnet is on the poles of the magnet.

 



Q 26 :    

Rashita and her friends were decorating the class bulletin board. She accidentally dropped the box of stainless steel pins by mistake. She tried to collect the pins using a magnet. She could not succeed. Why?

  • They are not using the magnet in right direction

     

  • Steel pins are very heavy and cannot be lifted magnet

     

  • Steel pins are very long

     

  • Steel is not magnetic in nature

     

(4)

As steel is not magnetic in nature, so it is not attracted by the magnet.

 



Q 27 :    

If the current is passing through a straight conductor, then, the magnetic field lines around it forms a particular shape. That shape is:

  • Straight lines

     

  • Concentric circles

     

  • Concentric ellipse

     

  • Concentric parabolas

     

(2)

When current passes through a straight conductor, then the magnetic field lines forms concentric circle around it.

 



Q 28 :    

The figure given below shows the magnetic field produced by a currents carrying wire. Which of the diagram shows it correctly?

  • A

     

  • B

     

  • C

     

  • D

     

(3)

As when current flows through current-carrying wire, then direction of magnetic field is calculated by right hand thumb rule.

 



Q 29 :    

Consider the following statements and choose the correct are:

  • A magnet is an object which attracts pieces of iron, Nickel and cobalt

     

  • Magnetic effect of electric current means that an electric current flowing in a wire produces a magnetic field around it

     

  • The end of a freely suspended magnet which points towards the north direction is called the north pole of the magnet

     

  • All of the above

     

(4)

(a) A magnet is an object which attracts pieces of iron, Nickel and cobalt.
(b) Magnetic effect of electric current means that an electric current flowing in a wire produces a magnetic field around it.
(c) The end of a freely suspended magnet which points towards the north direction is called the north pole of the magnet.

 



Q 30 :    

A rectangular loop carrying a current I is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in plane of the loop. If steady current I is created in wire as shown in figure below, then the loop:

  • Rotate about an axis parallel to the wire

     

  • Move towards the wire

     

  • Move away from the wire or towards right

     

  • Remains stationary

     

(2)

Force   F=μ02i1i24πr F1rAs r1<r2 F1>F2 Fnet=F1-F2

                   (Directed towards the wire)