Q 21 :    

AB

The molecule A changes into its isomeric form B by following a first order kinetics at a temperature of 1000 K. If the energy barrier with respect to reactant energy for such isomeric transformation is 191.48 kJ mol-1 and the frequency factor is 1020, the time required for 50% molecules of A to become B is ______ picoseconds (nearest integer).

[R = 8.314 J K-1mol-1]                 [2025]



(69)

Activation energy  Ea=191.48kJ mol-1=191480J mol-1

Frequency factor (A)=1020

Temperature (T)=1000 K

Gas constant R = 8.314 J/mol K

By Arrhenius equation,

=Ae-EaRT=1020e-1914808.314×1000

=1020e-23.03=1020e-ln10×10

=1020e-ln1010

=1020eln1010=10201010=1010s-1

t1/2=0.693k=0.6931010s=69.3×10-12s

=69.3 picosecond69 picosecond