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The condensation of an aromatic aldehyde (without $\mathrm{\alpha }$ hydrogen) with an aliphatic aldehyde or ketone (having $\mathrm{\alpha }$ hydrogen) in the presence of a strong base (hydroxide or alkoxide) to give $\mathrm{\alpha }$, $\mathrm{\beta }$ unsaturated aldehydes or ketones is called Claisen-Schmidt condensation reaction.

$\text{Moles of dibenzalacetone}=\frac{\text{Mass of dibenzalacetone}}{\text{molar mass}}$

                                                   $=\frac{351}{234} \text{mol}=1.5 \text{mol}$

By stoichiometry of reaction, moles of benzaldehyde = 2 $\times$moles of dibenzalacetone = 2 $\times$1.5 = 3mol.

Mass of benzaldehyde = moles of benzaldehyde $\times$molar mass of benzaldehyde = 3mol $\times$106 ${\mathrm{gmol}}^{-1}$ = 318 g

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