Q 1 :    

In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is _______ g. (Nearest integer)                      [2024]



(318)

The condensation of an aromatic aldehyde (without α hydrogen) with an aliphatic aldehyde or ketone (having α hydrogen) in the presence of a strong base (hydroxide or alkoxide) to give α, β unsaturated aldehydes or ketones is called Claisen-Schmidt condensation reaction.

Moles of dibenzalacetone=Mass of dibenzalacetonemolar mass

                                                   =351234mol=1.5mol

By stoichiometry of reaction, moles of benzaldehyde = 2 ×moles of dibenzalacetone = 2 ×1.5 = 3mol.

Mass of benzaldehyde = moles of benzaldehyde ×molar mass of benzaldehyde = 3mol ×106 gmol-1 = 318 g