When vapours of a secondary alcohol is passed over heated copper at 573 K, the product formed is [2019]
a carboxylic acid
an aldehyde
a ketone
an alkene
(3)

In the reaction,

the electrophile involved is [2018]
dichloromethyl cation
formyl cation
dichloromethyl anion
dichlorocarbene
(4)
It is Reimer–Tiemann reaction. The electrophile formed is dichlorocarbene which is formed according to the following mechanism:

Compound A, , is found to react with (produced by reacting Y with NaOH) and yields a yellow precipitate with characteristic smell. A and Y are respectively [2018]




(3)
As the compound is giving yellow precipitate with that shows it is undergoing haloform reaction. Haloform reaction is shown by the compounds having

Identify the major products P, Q and R in the following sequence of reactions: [2018]





(4)

Which one is the most acidic compound? [2017]




(3)
Electron withdrawing groups increase the acidity while electron donating groups decrease the acidity of phenol.
Reaction of phenol with chloroform in presence of dilute sodium hydroxide finally introduces which one of the following functional group? [2015]
–COOH
–
–CHO
–
(3)
This is Reimer–Tiemann reaction.

Which of the following reaction(s) can be used for the preparation of alkyl halides? [2015]
(I)
(II)
(III)
(IV)
(I) and (II) only
(IV) only
(III) and (IV) only
(I), (III) and (IV) only
(4)
1° and 2° alcohols react with HCl in presence of anhydrous as catalyst while in case of 3° alcohols anhydrous is not required.
Which of the following will not be soluble in sodium hydrogen carbonate? [2014]
2,4,6-Trinitrophenol
Benzoic acid
o-Nitrophenol
Benzenesulphonic acid
(3)
The reaction is as follows :
Among all the given compounds, o-nitrophenol is weaker acid than . Hence, it does not react with