Q 11 :    

When vapours of a secondary alcohol is passed over heated copper at 573 K, the product formed is           [2019]

  • a carboxylic acid

     

  • an aldehyde

     

  • a ketone

     

  • an alkene

     

(3)

[IMAGE 120]

 



Q 12 :    

In the reaction,

[IMAGE 121]

the electrophile involved is                    [2018]

  • dichloromethyl cation (C+HCl2)

     

  • formyl cation (C+HO)

     

  • dichloromethyl anion (C¯HCl2)

     

  • dichlorocarbene (:CCl2)

     

(4)

It is Reimer–Tiemann reaction. The electrophile formed is dichlorocarbene (:CCl2) which is formed according to the following mechanism:

[IMAGE 122]

 



Q 13 :    

Compound A, C8H10O, is found to react with NaOI (produced by reacting Y with NaOH) and yields a yellow precipitate with characteristic smell. A and Y are respectively       [2018]

  • [IMAGE 123]

     

  • [IMAGE 124]

     

  • [IMAGE 125]

     

  • [IMAGE 126]

     

(3)

As the compound is giving yellow precipitate with NaOI that shows it is undergoing haloform reaction. Haloform reaction is shown by the compounds having

[IMAGE 127]

 



Q 14 :    

Identify the major products P, Q and R in the following sequence of reactions:              [2018]

[IMAGE 128]

  • [IMAGE 129]

     

  • [IMAGE 130]

     

  • [IMAGE 131]

     

  • [IMAGE 132]

     

(4)

[IMAGE 133]

 



Q 15 :    

Which one is the most acidic compound?             [2017]

  • [IMAGE 134]

     

  • [IMAGE 135]

     

  • [IMAGE 136]

     

  • [IMAGE 137]

     

(3)

Electron withdrawing groups increase the acidity while electron donating groups decrease the acidity of phenol.

 



Q 16 :    

Reaction of phenol with chloroform in presence of dilute sodium hydroxide finally introduces which one of the following functional group?         [2015]

  • –COOH

     

  • CHCl2

     

  • –CHO

     

  • CH2Cl

     

(3)

This is Reimer–Tiemann reaction.

[IMAGE 138]

 

 



Q 17 :    

Which of the following reaction(s) can be used for the preparation of alkyl halides?             [2015]

(I)  CH3CH2OH+HClAnh. ZnCl2
(II)  CH3CH2OH+HCl
(III)  (CH3)3COH+HCl
(IV)  (CH3)2CHOH+HClAnh. ZnCl2

  • (I) and (II) only

     

  • (IV) only

     

  • (III) and (IV) only

     

  • (I), (III) and (IV) only

     

(4)

1° and 2° alcohols react with HCl in presence of anhydrous ZnCl2 as catalyst while in case of 3° alcohols anhydrous ZnCl2 is not required.

 



Q 18 :    

Which of the following will not be soluble in sodium hydrogen carbonate?        [2014]

  • 2,4,6-Trinitrophenol

     

  • Benzoic acid

     

  • o-Nitrophenol

     

  • Benzenesulphonic acid

     

(3)

The reaction is as follows :

Acid+NaHCO3  Sodium salt of acid(soluble)+H2CO3

Among all the given compounds, o-nitrophenol is weaker acid than HCO3-. Hence, it does not react with NaHCO3.