Q 1 :    

On Celsius scale the temperature of body increases by 40°C. The increase in temperature on Fahrenheit scale is                [2024]

  • 68° F

     

  • 70° F

     

  • 72° F

     

  • 75° F

     

(3) 

         C-0100=F-32180

         C=59(F-32)C=59F

         40=59FF=72oF

         40o change on Celsius scale will corresponds to 72o change on Fahrenheit scale.

 



Q 2 :    

A block of ice at −10°C is slowly heated and converted to steam at 100°C. Which of the following curves represent the phenomenon qualitatively?    [2024]

  •  

  •  

  •  

  •  

(4)

-10°C ice  changeTemp.0°C ice changeTemp.0°C

 water  changeTemp.100°C waterPhase change100°C steam

In this process, there are two phase changes and two temperature changes.



Q 3 :    

An amount of ice of mass 103 kg and temperature –10°C is transformed to vapour of temperature 110°C by applying heat. The total amount of work required for this conversion is, (Take, specific heat of ice = 2100 J kg1 K1, specific heat of water = 4180 J kg1 K1, specific heat of steam = 1920 J kg1 K1, Latent heat of ice = 3.35×105 J kg1 and Latent heat of steam = 2.25×106 J kg1)          [2025]

  • 3022 J

     

  • 3043 J

     

  • 3003 J

     

  • 3024 J

     

(2)

First, Ice at –10°C Q1 Ice at 0°C Q2 Water 0°C. Then, Water at 0°C Q3 Water at 100°C Q4 Vapour at 100°C Q5 Vapour at 110°C

Q1=m×SI×T=103×2100×10=21 J

Q2=m×Lf=103×3.35×105=335 J

Q3=m×Sw×T=103×4180×100=418 J

Q4=m×Lv=103×2.25×106=2250 J

Q5=m×Sv×T=103×1920×10=19.2 J

Qnet=3043. 2 J



Q 4 :    

A gun fires a lead bullet of temperature 300 K into a wooden block. The bullet having melting temperature of 600 K penetrates into the block and melts down. If the total heat required for the process is 625 J, then the mass of the bullet is ______ grams.

(Latent heat of fusion of lead =25×104 J Kg1 and specific heat capacity of lead =125 J Kg1 K1)          [2025]

  • 20

     

  • 15

     

  • 10

     

  • 5

     

(3)

Q=msT+mL

625=m×125×300+m×2.5×104

625=m{3.75+2.5}×104

 m=625625×104 kg=10 g



Q 5 :    

Which of the following figure represents the relation between Celsius and Fahrenheit temperatures?          [2025]

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  •  

  •  

  •  

(2)

C5=F329  C=5F91609

Clearly slope is +ve and intercept is –ve



Q 6 :    

Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. (Take, g = 10 m/s2 specific heat of water = 4200 J/(kg K))          [2025]

  • 0.23 K

     

  • 0.36 K

     

  • 0.14 K

     

  • 0.48 K

     

mgh=msT

T=ghs=10×2004200=0.48 K