Variables of Motion questions | Variables of Motion jee questions

Q 1 :

A bullet is fired into a fixed target looses one third of its velocity after travelling 4cm. It penetrates further $D \times 10^{- 3}$ m before coming to rest. The value of D is [2024]

32
5
3
4

1

2

3

4

(1)

$v^{2} - u^{2} = 2 a s$

${(\frac{2 u}{3})}^{2} = u^{2} + 2 (- a) (4 \times 10^{- 2})$

$\frac{4 u^{2}}{9} = u^{2} - 2 a (4 \times 10^{- 2})$

$- \frac{5 u^{2}}{9} = - 2 a (4 \times 10^{- 2})$ ...(1)

$0 = {(\frac{2 u}{3})}^{2} + 2 (- a) (x)$

$- \frac{4 u^{2}}{9} = - 2 a x$ ...(2)

$(1) / (2), \frac{5}{4} = \frac{4 \times 10^{- 2}}{x}$

$x = \frac{16}{5} \times 10^{- 2}$

$x = 3.2 \times 10^{- 2} m$

Q 2 :

A particle is moving in a straight line. The variation of position $' x'$ as a function of time $' t'$ is given as $x = (t^{3} - 6 t^{2} + 20 t + 15)$ m. The velocity of the body when its acceleration becomes zero is [2024]

6 m/s
10 m/s
8 m/s
4 m/s

1

2

3

4

(3)

$x = t^{3} - 6 t^{2} + 20 t + 15$

$\frac{d x}{d t} = v = 3 t^{2} - 12 t + 20$

$\frac{d v}{d t} = a = 6 t - 12$

When $a = 0$

$t = 2 s e c$

At $t = 2 s e c$

$v = 3 {(2)}^{2} - 12 (2) + 20 = 8 m / s$

Q 3 :

The relation between time $' t'$ and distance $' x'$ is $t = α x^{2} + β x,$ where $α$ and $β$ are constants. The relation between acceleration (a) and velocity (v) is [2024]

$a = - 2 α v^{3}$
$a = - 2 α v^{4}$
$a = - 2 α v^{2}$
$a = - 2 α v^{5}$

1

2

3

4

(1)

$t = α x^{2} + β x$ (differentiating wrt time)

$\frac{d t}{d x} = 2 α x + β$

$\frac{1}{v} = 2 α x + β$

(differentiating wrt time) $- \frac{1}{v^{2}} \frac{d v}{d t} = 2 α \frac{d x}{d t}$

$\frac{d v}{d t} = - 2 α v^{3}$

Q 4 :

A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^{2} = 1 + t^{2}$ . Its acceleration at any time $t$ is $x^{- n}$ where $n =$ _____. [2024]

(3) $x^{2} = 1 + t^{2} \Rightarrow x = \sqrt{1 + t^{2}}$

$v = \frac{d x}{d t} = \frac{1}{2 \sqrt{1 + t^{2}}} \cdot 2 t \Rightarrow v = \frac{t}{\sqrt{1 + t^{2}}}$

$a = \frac{d v}{d t} = \frac{\sqrt{1 + t^{2}} (1) - t \cdot \frac{1}{2} {(t^{2} + 1)}^{- 1 / 2} \cdot 2 t}{(1 + t^{2})}$

$a = \frac{\sqrt{1 + t^{2}} - \frac{t^{2}}{\sqrt{1 + t^{2}}}}{(1 + t^{2})} = \frac{t^{2} + 1 - t^{2}}{{(t^{2} + 1)}^{3 / 2}}$

$\Rightarrow a = \frac{1}{{(1 + t^{2})}^{3 / 2}} = \frac{1}{x^{3}} = x^{- 3} \Rightarrow n = 3$

Q 5 :

A particle is moving in one dimension (along x-axis) under the action of a variable force. It's initial position was 16 m right of origin. The variation of its position (x) with time (t) is given as $x = - 3 t^{3} + 18 t^{2} + 16 t,$ where x is in m and t in s. The velocity of the particle when its acceleration becomes zero is _____ m/s. [2024]

(52) $x = 3 t^{3} + 18 t^{2} + 16 t$

$v = - 9 t^{2} + 36 t + 16$

$a = - 18 t + 36$

$a = 0$ at $t = 2$ $s$

$v = - 9 {(2)}^{2} + 36 \times 2 + 16$

$v = 52 m / s$

Q 6 :

A particle initially at rest starts moving from reference point. $x = 0$ along x-axis, with velocity $v$ that varies as $v = 4 \sqrt{x}$ m/s. The acceleration of the particle is _____ $m s^{- 2}$ . [2024]

(8) Given, $v = 4 \sqrt{x}$

$‐ ‐ ‐ □ ‐ ‐ ‐ \to ‐ ‐ ‐ ‐ ‐ ‐ ‐ ‐ x - a x i s$

$x = 0, t = 0$

$a = \frac{v d v}{d x} = (4 \sqrt{x}) \frac{d (4 \sqrt{x})}{d x} = 16 \sqrt{x} \cdot \frac{1}{2 \sqrt{x}}$

$16 \sqrt{x} \cdot \frac{1}{2 \sqrt{x}} = 8 {m / s}^{2}$

Q 7 :

A train starting from rest first accelerates uniformly up to a speed of 80 km/h for time t, then it moves with a constant speed for time 3t. The average speed of the train for this duration of journey will be (in km/h) : [2024]

30
80
40
70

1

2

3

4

(4)

$Average speed = \frac{Distance}{Time} = \frac{\frac{1}{2} (t) (80) + 80 \times 3 t}{4 t}$

$V_{av} = \frac{40 t + 240 t}{4 t} = \frac{280}{4} = 70 km/hr$

Q 8 :

A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is [2024]

8.8 m/s
10 m/s
9.2 m/s
8 m/s

1

2

3

4

(4)

$B C \Rightarrow s = 9 t + 15 t = 24 t$

$A C \Rightarrow s = 6 t_{1} = 24 t \Rightarrow t_{1} = 4 t$

$v_{av} = \frac{dist.}{time} = \frac{48 t}{2 t + t_{1}}$

$\Rightarrow v_{av} = \frac{48 t}{2 t + 4 t} \Rightarrow \frac{48 t}{6 t} \Rightarrow 8 m/s$

Q 9 :

A sportsman runs around a circular track of radius r such that he traverses the path A B A B. The distance travelled and displacement, respectively, are [2025]

$2 r, 3 π r$
$3 π r, π r$
$π r, 3 r$
$3 π r, 2 r$

1

2

3

4

(4)

Displacement = 2r

Distance = $2 π r + π r = 3 π r$

Q 10 :

A particle moves along the x-axis and has its displacement x varying with time t according to the equation $x = c_{0} (t^{2} - 2) + c {(t - 2)}^{2}$ where $c_{0}$ and c are constants of appropriate dimensions. Then, which of the following statements is correct? [2025]

the acceleration of the particle is $2 c_{0}$
the acceleration of the particle is 2c
the initial velocity of the particle is 4c
the acceleration of the particle is $2 (c + c_{0})$

1

2

3

4

(4)

$x = C_{0} (t^{2} - 2) + C (t^{2} + 4 - 4 t)$

$v = \frac{d x}{d t} = 2 t C_{0} + 2 C (t - 2)$

$a = \frac{d v}{d t} = 2 C_{0} + 2 C$

Q 11 :

A person travelling on a straight line moves with a uniform velocity $v_{1}$ for a distance x and with a uniform velocity $v_{2}$ for the next $\frac{3}{2} x$ distance. The average velocity in this motion is $\frac{50}{7}$ m/s. If $v_{1}$ is 5 m/s then $v_{2}$ = __________ m/s. [2025]

(10)

$v_{avg} = \frac{x_{1} + x_{2}}{t_{1} + t_{2}}$

$\Rightarrow \frac{50}{7} = \frac{x + \frac{3 x}{2}}{\frac{x}{5} + \frac{3 x}{2 v_{2}}}$

$\Rightarrow \frac{50}{7} = \frac{5 / 2}{\frac{1}{5} + \frac{3}{2 v_{2}}}$

$\Rightarrow v_{2} = 10 m / s$

Q 12 :

The distance travelled by a particle is related to time t as $x = 4 t^{2}$ . The velocity of the particle at t = 5 s is [2023]

8 ${ms}^{- 1}$
20 ${ms}^{- 1}$
25 ${ms}^{- 1}$
40 ${ms}^{- 1}$

1

2

3

4

(4)

$x = 4 t^{2}$

$v = \frac{d x}{d t} = 8 t$

$At t = 5 s,$

$v = 8 \times 5 = 40 m/s$

Q 13 :

A vehicle travels 4 km with speed of 3 km/h and another 4 km with speed of 5 km/h, then its average speed is [2023]

4.25 km/h
3.50 km/h
4.00 km/h
3.75 km/h

1

2

3

4

(4)

$\frac{2}{V_{av}} = \frac{1}{3} + \frac{1}{5} = \frac{8}{15}$

$\Rightarrow V_{av} = \frac{15}{4} = 3.75 km/h$

Q 14 :

An object moves with speeds $v_{1}$ , $v_{2}$ and $v_{3}$ along the line segments AB, BC and CD respectively as shown in the figure. Where AB = BC and AD = 3AB, then the average speed of the object will be: [2023]

$\frac{(v_{1} + v_{2} + v_{3})}{3}$
$\frac{v_{1} v_{2} v_{3}}{3 (v_{1} v_{2} + v_{2} v_{3} + v_{3} v_{1})}$
$\frac{3 v_{1} v_{2} v_{3}}{v_{1} v_{2} + v_{2} v_{3} + v_{3} v_{1}}$
$\frac{(v_{1} + v_{2} + v_{3})}{3 v_{1} v_{2} v_{3}}$

1

2

3

4

(3)

$A B = x and B C = x$

$2 x + C D = 3 x$

$\Rightarrow C D = x$

$< v > = \frac{3 x}{\frac{x}{v_{1}} + \frac{x}{v_{2}} + \frac{x}{v_{3}}} = \frac{3 v_{1} v_{2} v_{3}}{v_{2} v_{3} + v_{1} v_{3} + v_{1} v_{2}}$

Q 15 :

A car travels a distance of $' x'$ with speed $v_{1}$ and then the same distance $' x'$ with speed $v_{2}$ in the same direction. The average speed of the car is: [2023]

$\frac{v_{1} v_{2}}{2 (v_{1} + v_{2})}$
$\frac{2 x}{v_{1} + v_{2}}$
$\frac{2 v_{1} v_{2}}{v_{1} + v_{2}}$
$\frac{v_{1} + v_{2}}{2}$

1

2

3

4

(3)

$V_{avg} = \frac{S + S}{\frac{S}{V_{1}} + \frac{S}{V_{2}}} = \frac{2 V_{1} V_{2}}{V_{1} + V_{2}}$

Q 16 :

A person travels $x$ distance with velocity $v_{1}$ and then $x$ distance with velocity $v_{2}$ in the same direction. The average velocity of the person is $v$ , then the relation between $v$ , $v_{1}$ and $v_{2}$ will be: [2023]

$v = v_{1} + v_{2}$
$v = \frac{v_{1} + v_{2}}{2}$
$\frac{2}{v} = \frac{1}{v_{1}} + \frac{1}{v_{2}}$
$\frac{1}{v} = \frac{1}{v_{1}} + \frac{1}{v_{2}}$

1

2

3

4

(3)

$Average velocity = \frac{x + x}{\frac{x}{v_{1}} + \frac{x}{v_{2}}} = v$

$\frac{1}{v_{1}} + \frac{1}{v_{2}} = \frac{2}{v}$

Q 17 :

The distance travelled by an object in time $t$ is given by $s = (2.5) t^{2} .$ The instantaneous speed of the object at $t$ = 5 s will be: [2023]

12.5 ${ms}^{- 1}$
62.5 ${ms}^{- 1}$
5 ${ms}^{- 1}$
25 ${ms}^{- 1}$

1

2

3

4

(4)

$Distance (s) = (2.5) t^{2}$

$Speed (v) = \frac{d s}{d t} = \frac{d}{d t} {(2.5) t^{2}}$

$v = 5 t$

$At t = 5, v = 5 \times 5 = 25 m/s$

Option (4) is correct

Q 18 :

The position of a particle related to time is given by $x = (5 t^{2} - 4 t + 5) m .$ The magnitude of velocity of the particle at $t = 2 s$ will be: [2023]

${10 ms}^{- 1}$
${14 ms}^{- 1}$
${16 ms}^{- 1}$
${6 ms}^{- 1}$

1

2

3

4

(3)

$x = 5 t^{2} - 4 t + 5$

$v = 10 t - 4$

$At t = 2 s, v = 16 m/s$

Q 19 :

A horse rider covers half the distance with 5 m/s speed. The remaining part of the distance was travelled with speed 10 m/s for half the time and with speed 15 m/s for the other half of the time. The mean speed of the rider averaged over the whole time of motion is $x / 7$ m/s. The value of $x$ is ______. [2023]

(50)

$t_{A B} = \frac{x}{5 m/s}$

In motion BC, $x = d_{1} + d_{2}$

where $d_{1}$ and $d_{2}$ are the distances travelled with 10 m/s and 15 m/s respectively in equal time intervals $\frac{' t'}{2}$ each.

$d_{1} = \frac{10 t}{2}, d_{2} = \frac{15 t}{2}$

$d_{1} + d_{2} = x = \frac{t}{2} (10 + 15) = \frac{25 t}{2}$

$< v > = \frac{2 x}{\frac{x}{5} + \frac{2 x}{25}} = \frac{2 \times 25}{5 + 2} = \frac{50}{7} m/s$

Topic Question Set

Q 1 :

A bullet is fired into a fixed target looses one third of its velocity after travelling 4cm. It penetrates further $D \times 10^{- 3}$ m before coming to rest. The value of D is [2024]

Q 2 :

A particle is moving in a straight line. The variation of position $' x'$ as a function of time $' t'$ is given as $x = (t^{3} - 6 t^{2} + 20 t + 15)$ m. The velocity of the body when its acceleration becomes zero is [2024]

Q 3 :

The relation between time $' t'$ and distance $' x'$ is $t = α x^{2} + β x,$ where $α$ and $β$ are constants. The relation between acceleration (a) and velocity (v) is [2024]

Q 4 :

A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^{2} = 1 + t^{2}$ . Its acceleration at any time $t$ is $x^{- n}$ where $n =$ _____. [2024]

Q 6 :

A particle initially at rest starts moving from reference point. $x = 0$ along x-axis, with velocity $v$ that varies as $v = 4 \sqrt{x}$ m/s. The acceleration of the particle is _____ $m s^{- 2}$ . [2024]

Q 7 :

A train starting from rest first accelerates uniformly up to a speed of 80 km/h for time t, then it moves with a constant speed for time 3t. The average speed of the train for this duration of journey will be (in km/h) : [2024]

Q 8 :

A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is [2024]

Q 9 :

A sportsman runs around a circular track of radius r such that he traverses the path A B A B. The distance travelled and displacement, respectively, are [2025]

Q 10 :

A particle moves along the x-axis and has its displacement x varying with time t according to the equation $x = c_{0} (t^{2} - 2) + c {(t - 2)}^{2}$ where $c_{0}$ and c are constants of appropriate dimensions. Then, which of the following statements is correct? [2025]

Q 11 :

A person travelling on a straight line moves with a uniform velocity $v_{1}$ for a distance x and with a uniform velocity $v_{2}$ for the next $\frac{3}{2} x$ distance. The average velocity in this motion is $\frac{50}{7}$ m/s. If $v_{1}$ is 5 m/s then $v_{2}$ = __________ m/s. [2025]

Q 12 :

The distance travelled by a particle is related to time t as $x = 4 t^{2}$ . The velocity of the particle at t = 5 s is [2023]

Q 13 :

A vehicle travels 4 km with speed of 3 km/h and another 4 km with speed of 5 km/h, then its average speed is [2023]

Q 14 :

An object moves with speeds $v_{1}$ , $v_{2}$ and $v_{3}$ along the line segments AB, BC and CD respectively as shown in the figure. Where AB = BC and AD = 3AB, then the average speed of the object will be: [2023]

Q 15 :

A car travels a distance of $' x'$ with speed $v_{1}$ and then the same distance $' x'$ with speed $v_{2}$ in the same direction. The average speed of the car is: [2023]

Q 16 :

A person travels $x$ distance with velocity $v_{1}$ and then $x$ distance with velocity $v_{2}$ in the same direction. The average velocity of the person is $v$ , then the relation between $v$ , $v_{1}$ and $v_{2}$ will be: [2023]

Q 17 :

The distance travelled by an object in time $t$ is given by $s = (2.5) t^{2} .$ The instantaneous speed of the object at $t$ = 5 s will be: [2023]

Q 18 :

The position of a particle related to time is given by $x = (5 t^{2} - 4 t + 5) m .$ The magnitude of velocity of the particle at $t = 2 s$ will be: [2023]

Want Us to Email you About Special Offers & Updates?

Topic Question Set

Q 1 : A bullet is fired into a fixed target looses one third of its velocity after travelling 4cm. It penetrates further D×10-3 m before coming to rest. The value of D is [2024]

Q 2 : A particle is moving in a straight line. The variation of position 'x' as a function of time 't' is given as x=(t3-6t2+20t+15)m. The velocity of the body when its acceleration becomes zero is [2024]

Q 3 : The relation between time 't' and distance 'x' is t=αx2+βx, where α and β are constants. The relation between acceleration (a) and velocity (v) is [2024]

Q 4 : A particle moves in a straight line so that its displacement x at any time t is given by x2=1+t2. Its acceleration at any time t is x-n where n=_____. [2024]

Q 6 : A particle initially at rest starts moving from reference point. x=0 along x-axis, with velocity v that varies as v=4x m/s. The acceleration of the particle is _____ ms-2. [2024]

Q 7 : A train starting from rest first accelerates uniformly up to a speed of 80 km/h for time t, then it moves with a constant speed for time 3t. The average speed of the train for this duration of journey will be (in km/h) : [2024]

Q 8 : A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is [2024]

Q 9 : A sportsman runs around a circular track of radius r such that he traverses the path A B A B. The distance travelled and displacement, respectively, are [2025]

Q 10 : A particle moves along the x-axis and has its displacement x varying with time t according to the equation x=c0(t2–2)+c(t–2)2 where c0 and c are constants of appropriate dimensions. Then, which of the following statements is correct? [2025]

Q 11 : A person travelling on a straight line moves with a uniform velocity v1 for a distance x and with a uniform velocity v2 for the next 32x distance. The average velocity in this motion is 507 m/s. If v1 is 5 m/s then v2 = __________ m/s. [2025]

Q 12 : The distance travelled by a particle is related to time t as x=4t2. The velocity of the particle at t = 5 s is [2023]

Q 13 : A vehicle travels 4 km with speed of 3 km/h and another 4 km with speed of 5 km/h, then its average speed is [2023]

Q 14 : An object moves with speeds v1, v2 and v3 along the line segments AB, BC and CD respectively as shown in the figure. Where AB = BC and AD = 3AB, then the average speed of the object will be: [2023]

Q 15 : A car travels a distance of 'x' with speed v1 and then the same distance 'x' with speed v2 in the same direction. The average speed of the car is: [2023]

Q 16 : A person travels x distance with velocity v1 and then x distance with velocity v2 in the same direction. The average velocity of the person is v, then the relation between v, v1 and v2 will be: [2023]

Q 17 : The distance travelled by an object in time t is given by s=(2.5)t2. The instantaneous speed of the object at t = 5 s will be: [2023]

Q 18 : The position of a particle related to time is given by x=(5t2-4t+5)m. The magnitude of velocity of the particle at t=2 s will be: [2023]

Want Us to Email you About Special Offers & Updates?

Q 1 :

A bullet is fired into a fixed target looses one third of its velocity after travelling 4cm. It penetrates further $D \times 10^{- 3}$ m before coming to rest. The value of D is [2024]

Q 2 :

A particle is moving in a straight line. The variation of position $' x'$ as a function of time $' t'$ is given as $x = (t^{3} - 6 t^{2} + 20 t + 15)$ m. The velocity of the body when its acceleration becomes zero is [2024]

Q 3 :

The relation between time $' t'$ and distance $' x'$ is $t = α x^{2} + β x,$ where $α$ and $β$ are constants. The relation between acceleration (a) and velocity (v) is [2024]

Q 4 :

A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^{2} = 1 + t^{2}$ . Its acceleration at any time $t$ is $x^{- n}$ where $n =$ _____. [2024]

Q 6 :

A particle initially at rest starts moving from reference point. $x = 0$ along x-axis, with velocity $v$ that varies as $v = 4 \sqrt{x}$ m/s. The acceleration of the particle is _____ $m s^{- 2}$ . [2024]

Q 7 :

A train starting from rest first accelerates uniformly up to a speed of 80 km/h for time t, then it moves with a constant speed for time 3t. The average speed of the train for this duration of journey will be (in km/h) : [2024]

Q 8 :

A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is [2024]

Q 9 :

A sportsman runs around a circular track of radius r such that he traverses the path A B A B. The distance travelled and displacement, respectively, are [2025]

Q 10 :

A particle moves along the x-axis and has its displacement x varying with time t according to the equation $x = c_{0} (t^{2} - 2) + c {(t - 2)}^{2}$ where $c_{0}$ and c are constants of appropriate dimensions. Then, which of the following statements is correct? [2025]

Q 11 :

A person travelling on a straight line moves with a uniform velocity $v_{1}$ for a distance x and with a uniform velocity $v_{2}$ for the next $\frac{3}{2} x$ distance. The average velocity in this motion is $\frac{50}{7}$ m/s. If $v_{1}$ is 5 m/s then $v_{2}$ = __________ m/s. [2025]

Q 12 :

The distance travelled by a particle is related to time t as $x = 4 t^{2}$ . The velocity of the particle at t = 5 s is [2023]

Q 13 :

A vehicle travels 4 km with speed of 3 km/h and another 4 km with speed of 5 km/h, then its average speed is [2023]

Q 14 :

An object moves with speeds $v_{1}$ , $v_{2}$ and $v_{3}$ along the line segments AB, BC and CD respectively as shown in the figure. Where AB = BC and AD = 3AB, then the average speed of the object will be: [2023]

Q 15 :

A car travels a distance of $' x'$ with speed $v_{1}$ and then the same distance $' x'$ with speed $v_{2}$ in the same direction. The average speed of the car is: [2023]

Q 16 :

A person travels $x$ distance with velocity $v_{1}$ and then $x$ distance with velocity $v_{2}$ in the same direction. The average velocity of the person is $v$ , then the relation between $v$ , $v_{1}$ and $v_{2}$ will be: [2023]

Q 17 :

The distance travelled by an object in time $t$ is given by $s = (2.5) t^{2} .$ The instantaneous speed of the object at $t$ = 5 s will be: [2023]

Q 18 :

The position of a particle related to time is given by $x = (5 t^{2} - 4 t + 5) m .$ The magnitude of velocity of the particle at $t = 2 s$ will be: [2023]