Consider the equation , where n [20, 100] is a natural number. Then the number of all distinct values of n, for which the given equation has integral roots, is equal to [2025]
5
7
6
8
(3)
we have,
But
.
6 integral values of 'n' are possible.
The product of all solutions of the equation , is: [2025]
e
(3)
We have,
Taking log on both sides, we get
Put ln x = t
.
The product of all the rational roots of the equation , is equal to [2025]
28
21
7
14
(4)
We have,
Let , then
Product of all rational roots = .
The number of real solution(s) of the equation is : [2025]
2
3
1
0
(1)
, |x + 2| is minimum and , |x – 3| is minimum.
From the graph, only two solutions.
The sum, of the squares of all the roots of the equation , is [2025]
(1)
Given,
Case I:
Case II :
Required sum =
.
If and are the roots , then is equal to : [2025]
–6
6
–2
2
(4)
We have,
So, .
The number of solutions of the equation is : [2025]
1
3
4
2
(3)
We have, ... (i)
Put in (i), we get
Number of solutions = 4.
If the set of all , for which the equation has no real root, is the interval , and , then is equal to : [2025]
2129
2119
2109
2139
(4)
Since, the given equation has no real root
.
Let be the roots of the equation with . Let . If , then is equal to __________. [2025]
31
We have,
... (i)
and
... (ii)
On solving equations (i) and (ii), we get a = 3, b = –4
.