Q 1 :    

If a rubber ball falls from a height h and rebounds up to the height of h/2. The percentage loss of total energy of the initial system as well as velocity ball before it strikes the ground, respectively, are                 [2024]

  • 40%,2gh

     

  • 50%,gh2

     

  • 50%,2gh

     

  • 50%,gh

     

(3)  

       Velocity just before collision = 2gh

        Velocity just after collision = 2g(h2)

             KE=12m(2gh)-12mgh=12mgh

             % loss in energy KEKEi×100

         KEKEi×100=12mgh12mg2h×100=50%

 



Q 2 :    

A spherical body of mass 100 g is dropped from a height of 10 m from the ground. After hitting the ground, the body rebounds to a height of 5 m. The impulse of force imparted by the ground to the body is given by (given g=9.8 m/s2)           [2024]

  • 4.32 kg ms-1

     

  • 43.2 kg ms-1

     

  • 23.9 kg ms-1

     

  • 2.39 kg ms-1

     

(4)

m=100g=0.1 kg, h1=10 m, h2=5 m

u=2gh1=2×98 m/s

v=2gh2=98 m/s

Impulse =ΔP=Pf-Pi

=0.1[98+2×98]

2.39 kg m/s



Q 3 :    

A simple pendulum of length 1 m has a wooden bob of mass 1 kg. It is struck by a bullet of mass 10-2 kg moving with a speed of 2×102 ms-1. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is (use g=10 m/s2)         [2024]

  • 0.30 m

     

  • 0.20 m

     

  • 0.35 m

     

  • 0.40 m

     

(2)

Pi=Pfmu=(M+m)V

mu=(M+m)V

10-2×2×1021×VV2 m/s

 



Q 4 :    

As shown below, bob A of a pendulum having massless string of length 'R' is released from 60° to the vertical. It hits another bob B of half the mass that is at rest on a friction less table in the centre. Assuming elastic collision, the magnitude of the velocity of bob A after the collision will be (Take g as acceleration due to gravity)          [2025]

  • 13Rg

     

  • Rg

     

  • 43Rg

     

  • 23Rg

     

(1)

Velocity of a just before hitting:

u=2gR2=gR

Just after collision, let velocity of A and B are v1 and v2 respectively

By COM: mu=mv1+m2v2

2v1+v2=2u         ... (i)

e=1=v2v1u

 v2v1=u          ... (ii)

From (i) and (ii)

 3v1=u  v1=u3=13gR



Q 5 :    

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : 

Three identical spheres of same mass undergo one dimensional motion as shown in figure with initial velocities VA = 5 m/s, VB = 2 m/s, VC = 4 m/s. If we wait sufficiently long for elastic collision to happen, then VA = 4 m/s, VB = 2 m/s, VC = 5 m/s will be the final velocities.

Reason (R) : In an elastic collision between identical masses, two objects exchange their velocities.

In the light of the above statements, choose the correct answer from the options given below:           [2025]

  • Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

     

  • (A) is true but (R) is false

     

  • Both (A) and (R) are true and (R) is the correct explanation of (A)

     

  • (A) is false but (R) is true

     

(4)

In elastic collision for same mass, velocities interchange for

Final velocity

VA = 2 m/s

VB = 4 m/s

VC = 5 m/s