Sugar which does not give reddish brown precipitate with Fehling’s reagent, is: [2024]
Sucrose
Lactose
Glucose
Maltose
(A)
Sucrose does not have an aldehydic or ketonic group. Hence sucrose is a non-reducing sugar and does not give reddish brown precipitate with Fehling’s reagent. All monosaccharides (such as glucose) are reducing sugars.
Match List I with List II
List I | List II | ||
A. | -Glucose and -Galactose | I. | Functional isomers |
B. | -Glucose and -Glucose | II. | Homologous |
C. | -Glucose and -Fructose | III. | Anomers |
D. | -Glucose and -Ribose | IV. | Epimers |
Choose the correct answer from the options given below: [2024]
A-III, B-IV, C-II, D-I
A-III, B-IV, C-I, D-II
A-IV, B-III, C-II, D-I
A-IV, B-III, C-I, D-II
(D)
A. Epimers are diastereomers that differ in configuration at only one chiral centre. -Glucose and -Galactose are C-4 epimers.
B. Anomers are epimers which differ in configuration at acetal or hemiacetal carbon. -D-glucose and -D-glucose are anomers.
C. Glucose is an aldohexose and fructose is a ketohexose. These are thus functional isomers.
D. Formula of glucose () differs by — unit with the formula of ribose (). So, Homologns
The incorrect statement about Glucose is: [2024]
Glucose remains in multiple isomeric form in its aqueous solution
Glucose is one of the monomer unit in sucrose
Glucose is an aldohexose
Glucose is soluble in water because of having aldehyde functional group.
(D)
1. Glucose exists as equilibrium mixture of -D-glucose, open chain structure and -D-glucose.
2. Sucrose is a disaccharide formed by glycosidic linkage between C1 of -D-glucose and C2 of -D-fructose.
3. Glucose is an aldohexose.
4. Water solubility of glucose is because it forms extensive hydrogen bonding with water.