Q 1 :    

ε0 and μ0 are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are 2ε0 and 1.5μ0 respectively, the refractive index of the medium will nearly be              [2023]
 

  • 2

     

  • 3

     

  • 3

     

  • 2

     

(2)

μ=cv=1μ0ε011.5μ0×2ε0=3



Q 2 :    

A light ray falls on a glass surface of refractive index 3, at an angle 60°. The angle between the refracted and reflected rays would be          [2022]

  • 30°

     

  • 60°

     

  • 90°

     

  • 120°

     

(3)

[IMAGE 268]

The refractive index of glass, μ=3

Angle of incidence = 60°

Let 'r' be the angle of refraction.

Now, applying Snell's law

1×sin60°=μ×sinr

32=3×sinr

sinr=12

r=30°

Let θ1+θ2, be the angle between reflected ray and refracted ray. 

Hence, from the figure we can say that

θ1+θ2=60°+30°=90°



Q 3 :    

An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is               [2016]

  • 8

     

  • 10

     

  • 12

     

  • 16

     

(3)

[IMAGE 269]

Here μ=1.5

l= length of the slab

x= position of air bubble from one side

As per question, total apparent length of slab = 5 + 3

or xμ+(l-x)μ=8  or  lμ=8                l=8μ=8×1.5=12 cm