jee main chemistry important questions | Organic Compounds Containing Nitrogen jee main questions FREE

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(B)

Aniline is IUPAC accepted name of aminobenzene.

(45)

$C_{2} H_{5} {NH}_{2} \overset{{NaNO}_{2} + HCl}{\to} C_{2} H_{5} N_{2}^{+}$

$\overset{H_{2} O}{\to} C_{2} H_{5} OH + N_{2}$

Moles of nitrogen

$(n_{N_{2}}) = \frac{Volume at STP in L}{22.4} = \frac{2.24}{22.4} mol = 0.1 mol$

From reaction it is clear that moles of ethylamine $(n_{C_{2} H_{5} {NH}_{2}}) = n_{N_{2}} = 0.1 mol .$

Mass of ethylamine = $n_{C_{2} H_{5} {NH}_{2}} \times$ molar mass of ethylamine

$= 0.1 mol \times 45 {g mol}^{- 1} = 45 \times 10^{- 1} g$

(9)

$HCl + NaOH \to NaCl + H_{2} O$

By stoichiometry

$n_{HCl} = n_{NaOH} = 0.2 mol$

$C_{2} H_{5} {NH}_{2} \overset{{NaNO}_{2} + HCl}{\to}$

$C_{2} H_{5} N_{2}^{+} {Cl}^{-} \overset{H_{2} O}{\to} C_{2} H_{5} OH + N_{2} + HCl$

$n_{C_{2} H_{5} {NH}_{2}} = n_{HCl} = 0.2 mol$

$W_{C_{2} H_{5} {NH}_{2}} (X) = M_{C_{2} H_{5} {NH}_{2}} \times n_{C_{2} H_{5} {NH}_{2}} = 45 \times 0.2 g = 9 g$

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