Topic Question Set


Q 1 :

Let A = {1, 2, 3, 4, 5, 6, 7}. Then the relation R={(x,y)A×A:x+y=7} is                     [2023]

  • an equivalence relation

     

  • reflexive but neither symmetric nor transitive

     

  • transitive but neither symmetric nor reflexive

     

  • symmetric but neither reflexive nor transitive

     

(4)

Given, A={1,2,3,4,5,6,7}

and R={(x,y)A×A:x+y=7}

For Reflexive: Let y=x

So, x+x=7x=72, which is not possible.

So, the given relation is not reflexive.

For Symmetric: xRyx+y=7

  y+x=7   xRyyRx

Hence, the given relation is symmetric.

For Transitive: Let xRy and yRzx+y=7 and y+z=7.

But it does not imply that x+z=7

So, R is not transitive.



Q 2 :

Let A = {2, 3, 4} and B = {8, 9, 12}. Then the number of elements in the relation

R={((a1,b1),(a2,b2))(A×B,A×B):a1 divides b2 and a2 divides b1} is                   [2023]

  • 24

     

  • 12 

     

  • 36 

     

  • 18

     

(3)

a1 divides b2

Each element has 2 choices. 

3×2=6

a2 divides b1 

Each element has 2 choices. 

3×2=6

Total number of relations is 6×6=36



Q 3 :

Let A = {1, 3, 4, 6, 9} and B = {2, 4, 5, 8, 10}. Let R be a relation defined on A x B such that R={((a1,b1),(a2,b2)):a1b2 and b1a2}. Then the number of elements in the set R is             [2023]

  • 52

     

  • 180 

     

  • 26 

     

  • 160

     

(4)

We have, A={1,3,4,6,9}; B={2,4,5,8,10}

R={((a1,b1),(a2,b2)):a1b2 and b1a2}

At a1=1, there are 5 choices for b2;

a1=3, there are 4 choices for b2

a1=4, there are 4 choices for b2

a1=6, there are 2 choices for b2;

a1=9, there is 1 choice for b2;

  Total ways for (a1b2)=16

Now, at b1=2, there are 4 choices for a2

b1=4, there are 3 choices for a2;

b1=5, there are 2 choices for a2

b1=8, there is 1 choice for a2

Total ways for (b1a2)=10

Required number of ways =16×10=160

 



Q 4 :

Let R be a relation on R, given by

R = {(a,b):3a-3b+7 is an irrational number}.

Then R is                                                         [2023]

  • reflexive and symmetric but not transitive

     

  • reflexive and transitive but not symmetric

     

  • reflexive but neither symmetric nor transitive

     

  • an equivalence relation

(3)

R={(a,b):3a-3b+7 is an irrational number}

Reflexive: For (a,a), we have 3a-3a+7=7, which is an irrational number. R is reflexive.

Symmetric: Let (a,b)R, i.e., 3a-3b+7 is an irrational number.

Now, we need to check (b,a)R or not.

Let 3a=7 and 3b=8

Then 3a-3b+7=7-8+7=27-8, which is an irrational number.

But 3b-3a+7=8-7+7=8, which is not an irrational number.

For (a,b)R(b,a)R.

R is not symmetric.

Transitive: Let (a,b) and (b,c)R.

Let 3a=8, 3b=27, 3c=7

Then 3a-3b+7=8-27+7=8-7, which is an irrational number.

Also, 3b-3c+7=27-7+7=27, which is an irrational number.

But 3a-3c+7=8-7+7=8, which is not an irrational(a,c)R.

  R is not transitive.



Q 5 :

Let P(S) denote the power set of S = {1, 2, 3, ...., 10}. Define the relations R1 and R2 on P(S) as AR1B if (ABC)(BAC)=ϕ and AR2B if ABC=BAC,A,BP(S). Then                  [2023]

  • both R1 and R2 are not equivalence relations

     

  • only R2 is an equivalence relation

     

  • only R1 is an equivalence relation

     

  • both R1 and R2 are equivalence relations

(4)

 



Q 6 :

The relation R={(a,b):gcd(a,b)=1,2ab,a,b,Z} is                      [2023]

 

  • reflexive but not symmetric

     

  • transitive but not reflexive

     

  • symmetric but not transitive 

     

  • neither symmetric nor transitive

     

(4)

Reflexive : gcd(a,a)=a1 for a1.

Symmetric: Let a=2, b=1

gcd(a,b)=1;  b2a

Thus, (2,1)R; gcd(1,2)=1. But 2=2×1

Therefore (1,2)R. Hence, R is not symmetric.

Transitive: (2,3)R

(3,8)R. But (2,8)R.

Hence R is not transitive.

R is neither symmetric nor transitive.



Q 7 :

Let R be a relation defined on  as a R b if 2a+3b is a multiple of 5, a,b.                   [2023]

  • symmetric but not transitive

     

  • not reflexive

     

  • an equivalence relation 

     

  • transitive but not symmetric

     

(3)

If 'R' be a relation defined on N as a R b is 2a+3b is a multiple of 5, a,bN.

(i) a R a5a is a multiple of 5

    R is a reflexive relation.

(ii) a R b,2a+3b=5α (let)

Now, b R a2b+3a=2b+(5α-3b2)·3

=152α-52b=52(3α-b)=52(2a+2b-2α)=5(a+b-α)

So, R is a symmetric relation.

(iii) a R b2a+3b=5αb R c2b+3c=5β

Now, 2a+5b+3c=5(α+β)

2a+5b+3c=5(α+β) or 2a+3c=5(α+β-b)

a R c

So, R is a transitive relation.

Hence Relation 'R' is an equivalence relation.



Q 8 :

The minimum number of elements that must be added to the relation R = {(a, b), (b, c)} on the set {a, b, c} so that it becomes symmetric and transitive is              [2023]

  • 3

     

  • 7

     

  • 4

     

  • 5

     

(2)

Given relation, R={(a,b),(b,c)} and set = {a,b,c}

For symmetric, since (a,b),(b,c)R

So, (b,a),(c,b) be in R. For transitive, since (a,b),(b,c)R

So, (a,c) should be in R. Then (c,a) should also be in R since (a,c) lies in R.

Since (a,b),(b,a)R, so (a,a)R should also lie in R.

Since (c,b),(b,c)R, so (c,c) should also lie in R.

Since (b,c),(c,b)R, so (b,b) should also lie in R.

  Elements to be added are:

(b,a),(c,b),(a,c),(c,a),(a,a),(c,c),(b,b).

Total number of elements to be added = 7.



Q 9 :

Let R be a relation on N x N defined by (a, b) R(c, d) if and only if ad(b-c)=bc(a-d). Then R is                  [2023]

  • transitive but neither reflexive nor symmetric

     

  • symmetric but neither reflexive nor transitive

     

  • symmetric and transitive but not reflexive

     

  • reflexive and symmetric but not transitive

     

(2)

We have, (a,b)R(c,d)ad(b-c)=bc(a-d)

b-cbc=a-dad  and  1c-1b=1d-1a1a-1b=1d-1c

For reflexive: (a,b)R(a,b)1a-1b=1b-1a which is false.

Hence, it is not reflexive.

For symmetric: (a,b)R(c,d)1a-1b=1d-1c

1c-1d=1b-1a(c,d)R(a,b)

Hence, it is symmetric.

For transitive: (a,b)R(c,d)1a-1b=1d-1c

and (c,d)R(e,f)1c-1d=1f-1e

1a-1b=1e-1f(a,b)R(e,f)

Hence, it is not transitive.



Q 10 :

Among the relations

S={(a,b):a,bR-{0},2+ab>0} and 

T={(a,b):a,bR,a2-b2Z}                                      [2023]

  • S is transitive but T is not

     

  • both S and T are symmetric

     

  • neither S nor T is transitive   

     

  • T is symmetric but S is not

     

(4)

For relation T=a2-b2I

Then, (b,a) on relation Rb2-a2I

T is symmetric, S={(a,b):a,bR-{0},2+ab>0}

2+ab>0ab>-2ba>-12

If (b,a)S, then 2+ba is not necessarily positive.

   S is not symmetric.



Q 11 :

Let A = {1, 2, 3, 4, .... ,10} and B = {0, 1, 2, 3, 4}. The number of elements in the relation R={(a,b)A×A:2(a-b)2+3(a-b)B} is __________ .           [2023]



(18)

A={1,2,3,4,,10}B={0,1,2,3,4}

R={(a,b)A×A:2(a-b)2+3(a-b)B}

Now, 2(a-b)2+3(a-b)=(a-b)[2(a-b)+3]B

a=b or a-b=-2

When a=b10 ordered pairs

When a-b=-28 ordered pairs. Total =18



Q 12 :

Let A = {0, 3, 4, 6, 7, 8, 9, 10} and R be the relation defined on A such that R={(x,y)A×A:x-y is odd positive integer or x-y=2}. The minimum number of elements that must be added to the relation R, so that it is a symmetric relation, is equal to __________ .              [2023]



(19)

A={0,3,4,6,7,8,9,10}

R={(x,y)A×A:x-y is an odd positive integer or x-y=2}

 Possible pairs to be added are 

{(0,3),(0,7),(0,9),(3,4),(3,6),(3,8),(3,10),(4,7),(4,9),(6,7),(6,9), (7,8),(7,10),(8,9),(9,10),(4,6),(6,8),(7,9),(8,10)}

  We need to add a minimum of 19 elements to form it symmetric.

 



Q 13 :

The number of relations, on the set {1, 2, 3} containing (1, 2) and (2, 3), which are reflexive and transitive but not symmetric, is _________ .               [2023]



(3)

Let we have set A={1,2,3}

By definition, we can say that

For reflexivity: (1,1),(2,2),(3,3)R  ...(i)

For symmetry: (2,1),(1,2)R  ...(ii)

For transitivity: (1,2)R and (2,3)R(1,3)R  ...(iii)

But according to the question,

For not symmetric: (2,1) and (3,2)R  ...(iv)

So, R1={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)}

R2={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3),(2,1)}

and R3={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3),(3,2)}



Q 14 :

Let A = {-4, -3, -2, 0, 1, 3, 4} and R={(a,b)A×A:b=|a|or b2=a+1} be a relation on A.

Then the minimum number of elements, that must be added to the relation R so that it becomes reflexive and symmetric, is ________ .                 [2023]



(7)

R={(-4,4),(-3,3),(3,-2),(0,1),(0,0),(1,1),(4,4),(3,3)}

For reflexive, number of elements added to the relation R is  (-2,2),(-4,-4),(-3,-3)

For symmetric, number of elements added to the relation is  (4,-4),(3,-3),(-2,3),(1,0)

So, total number of elements =3+4=7



Q 15 :

Let A = {1, 2, 3, 4} and R be a relation on the set A x A defined by R={((a,b),(c,d)):2a+3b=4c+5d}.

Then the number of elements in R is ___________ .                                                                                    [2023]



(6)

A={1,2,3,4}

A×A={(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4), (3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

R={((a,b),(c,d)):2a+3b=4c+5d}

On checking the elements of A×A, we get:

{((1,4),(1,2)),((2,3),(2,1)),((3,1),(1,1)),((3,4),(2,2)), ((4,2),(1,2)),((4,3),(3,1))} will satisfy R.

Number of elements in R=6



Q 16 :

The minimum number of elements that must be added to the relation R = {(a, b), (b, c), (b, d)} on the set {a, b, c, d} so that it is an equivalence relation is _____________ .    [2023]



(13)

Given S={(a,b),(b,c),(b,d)}

Reflexive:(a,a),(b,b),(c,c),(d,d)Symmetric:(b,a),(c,b),(d,b)Transitive:(a,c),(a,d),(d,c)(c,a)(d,a)(c,d)

So, 13 elements must be added.



Q 17 :

Let a relation R on N×N be defined as:

(x1,y1)R(x2,y2) if and only if x1x2 or y1y2.

Consider the two statements:

(I) R is reflexive but not symmetric.

(II) R is transitive.

Then which one of the following is true?                      [2024]

  • Both (I) and (II) are correct.

     

  • Neither (I) nor (II) is correct.

     

  • Only (I) is correct.

     

  • Only (II) is correct.

     

(3)

   (x1,y1)R(x2,y2)

   x1x2 or y1y2

   For reflexive :

   (x1,y1)R(x1,y1)

   x1x1 or y1y1 which is true.

   So, R is reflexive.

   For symmetric:

   When (x1,y1)R(x2,y2)

   x1x2 or y1y2

   x2x1 or y2y1

   They may or may not be true.

   For example (1, 2) and (3, 4)

   13 and 24 but 31 and 42.

       R is not symmetric.

   For transitive :

   Take pairs as (3, 9), (4, 6), (2, 7)

   (3,9)R(4,6) as 43

   (4,6)R(2,7) as 76

   But (3,9)R(not)(2,7), as neither 23 nor 79

   So, R is not transitive.

 



Q 18 :

Let the relations R1 and R2 on the set X={1,2,3,...,20} be given by R1={(x,y):2x-3y=2} and R2={(x,y):-5x+4y=0}. If M and N be the minimum number of elements required to be added in R1 and R2, respectively, in order to make the relations symmetric, then M+N equals                  [2024]

  • 10

     

  • 8

     

  • 16

     

  • 12

     

(1)

    R1={(x,y):2x-3y=2}

    R1={(4,2),(7,4),(10,6),(13,8),(16,10),(19,12)}

   So, 6 elements are needed to make R1 symmetric

   M=6

   R2={(x,y):-5x+4y=0}

   R2={(4,5),(8,10),(12,15),(16,20)}

   So, 4 elements are needed to make R2 symmetric

  N=4

  M+N=6+4=10



Q 19 :

Let A={1, 2, 3, 4, 5}. Let R be a relation on A defined by xRy if and only if 4x5y. Let m be the number of elements in R and n be the minimum number of elements from A×A that are required to be added to R to make it a symmetric relation. Then m+n is equal to:            [2024]

  • 24

     

  • 26

     

  • 25

     

  • 23

     

(3)

   Given, A={1,2,3,4,5}

   R={(x,y):4x5y,x,yA}

   R={(1,1),(1,2),(1,3),(1,4),(1,5),(2,2),(2,3),(2,4),(2,5),(3,3),(3,4),(3,5),(4,4),(4,5),(5,4),(5,5)}

     n(R)=16=m

   Elements needed to make R symmetric={(2,1),(3,1),(4,1),(5,1),(3,2),(4,2),(5,2),(4,3),(5,3)}  i.e., 9 elements

     n=9

   So, m+n=16+9=25

 



Q 20 :

Let A = {2, 3, 6, 8, 9, 11} and B = {1, 4, 5, 10, 15}. Let R be a relation on A×B defined by (a, b) R(c, d) if and only if 3ad−7bc is an even integer. Then the relation R is                               [2024]

  • an equivalence relation.

     

  • reflexive and symmetric but not transitive.

     

  • reflexive but not symmetric.

     

  • transitive but not symmetric.

     

(2)

   We have, (a,b)R(c,d)3ad-7bc is an even integer.

   For reflexive : (a,b)R(a,b)3ab-7ab=-4ab, which is an even integer.

   For symmetric, (a,b)R(c,d)3ad-7bc is an even integer.

    3ad-7bc+4bc+4ad is also an even integer

                                                      (even + even = even number)

   7ad-3bc is an even integer

  3cb-7da is also an even integer

  (c,d)R(a,b)

  For transitive, (a,b)R(c,d) and (c,d)R(e,f)

  3ad-7bc and 3cf-7de is an even integer.

  For a=2,b=5,c=6,d=8,e=9,f=1

  3af-7bc=3×2×1-7×5×9=6-315=-309, which is not an even integer.

     Given relation is not transitive.



Q 21 :

Consider the relations R1 and R2 defined as aR1ba2+b2=1 for all a,bR and (a,b)R2(c,d)a+d=b+c for all (a,b),(c,d)N×N. Then                 [2024]

  • R1 and R2 both are equivalence relations

     

  • Only R1 is an equivalence relation

     

  • Only R2 is an equivalence relation

     

  • Neither R1 nor R2 is an equivalence relation

     

(3)

  Consider, (x,x)R1

  Then, x2+x21 for any xR

      R1 is not reflexive

  Hence, R1 is not an equivalence relation.

  For R2

  (i) Let (x,y)R(x,y)x+y=y+x, which is true for all x,yN.

   R2 is reflexive.

  (ii) Let (x,y)R(z,p)x+p=y+zp+x=z+y

   z+y=p+x(z,p)R(x,y)

   R2 is symmetric.

  (iii) Let (a,b)R(c,d)a+d=b+c                ...(i)

         (c,d)R(e,f)c+f=d+e                        ...(ii)

  From (i) and (ii), we have a+d+c+f=b+c+d+e

              a+f=b+e(a,b)R(e,f)

   R2 is transitive.

  So, R2 is an equivalence relation.



Q 22 :

Let S = {1, 2, 3,…,10}. Suppose M is the set of all the subsets of S, then the relation R={(A,B):ABϕ;A,BM} is:               [2024]

  • symmetric and transitive only

     

  • reflexive only

     

  • symmetric and reflexive only

     

  • symmetric only

     

(4)

   Given, AMAA=ϕ, if A=ϕ

   So, R is not reflexive.

   If (A,B)RABϕBAϕ(B,A)R

   So, R is symmetric.

   If (A,B) and (B,C)RABϕ and BCϕ

   AC is not necessarily non-empty set.

   Hence, AC not necessarily belongs to R.

   So, R is not a transitive relation.

      Given relation is symmetric and reflexive only.

 



Q 23 :

Let R be a relation on Z×Z defined by (a, b) R (c, d) if and only if ad-bc is divisible by 5. Then R is              [2024]

  • Reflexive but neither symmetric nor transitive

     

  • Reflexive, symmetric and transitive

     

  • Reflexive and transitive but not symmetric

     

  • Reflexive and symmetric but not transitive

     

(4)

   Reflexive: For (a,b)R(a,b)

   ab-ab=0 is divisible by 5.

   So,(a,b)R(a,b)   a,bZ

      R is reflexive.

   Symmetric : For (a,b)R(c,d), if ad-bc is divisible by 5.

   Then, bc-ad is also divisible by 5.

   So,(c,d)R(a,b) a,b,c,dZ

  R is symmetric.

   Transitive : For (a,b)R(c,d)ad-bc is divisible by 5 and (c,d)R(e,f)cf-de is divisible by 5

   Let ad-bc=5 k1 and cf-de=5 k2, where k1 and k2 are integers.

   adf-bcf=5k1f                                     ...(i)

   and cfb-deb=5k2b                                ...(ii)

   Solving (i) and (ii), we get

   adf-bcf+cfb-deb=5k1f+5k2b

   adf-deb=5(k1f+k2b)d(af-be)=5(k1f+k2b)

   af-be is not divisible by 5 for  a,b,c,d,e,fZ

  So, R is not transitive.

    R is Reflexive and symmetric but not transitive.



Q 24 :

If R is the smallest equivalence relation on the set {1, 2, 3, 4} such that {(1,2),(1,3)}R, then the number of elements in R is _______ .             [2024]

  • 12

     

  • 15

     

  • 10

     

  • 8

     

(3)

   To make R an equivalence relation, R should be reflexive, symmetric, and transitive.

    R = {(1,1), (2,2), (3,3), (4,4), (1,2), (2,1), (1,3), (3,1), (3,2), (2,3)}

   So, minimum number of elements in R should be 10.

 



Q 25 :

Let A = {2, 3, 6, 7} and B = {4, 5, 6, 8}. Let R be a relation defined on A×B by (a1,b1)R(a2,b2) if and only if a1+a2=b1+b2. Then the number of elements in R is ______________.       [2024]



(25)

Given, A={2, 3, 6, 7} and B={4, 5, 6, 8} 

(a1,b1)R(a2,b2)a1+a2=b1+b2

(2,4)R(6,4)(3,6)R(7,4)(2,4)R(7,5)(3,5)R(7,5)(2,5)R(7,4)(6,5)R(7,8)(3,4)R(6,5)(6,8)R(7,5)(3,5)R(6,4)(7,6)R(7,8)(3,4)R(7,6)(6,4)R(6,8)(6,6)R(6,6)]×2

Hence, total number of elements = 13×2-1=25



Q 26 :

Let A = {1, 2, 3,…,20}. Let R1 and R2 be two relation on A such that R1 = {(a, b) : b is divisible by a} R2 = {(a, b) : a is an integral multiple of b} Then, number of elements in R1-R2 is equal to _______ .                [2024]



(46)

R1= {(1, 1), (1, 2)…(1, 20), (2, 2), (2, 4),…(2, 20), (3, 3), (3, 6)…(3, 18), (4, 4), (4, 8),…(4, 20), (5, 5), (5, 10), (5, 15), (5, 20), (6, 6), (6, 12), (6, 18), (7, 7), (7, 14), (8, 8), (8, 16), (9, 9), (9, 18), (10, 10), (10, 20), (11, 11), (12, 12), (13, 13), (14, 14), (15, 15), (16, 16), (17, 17), (18, 18), (19, 19), (20, 20)}

R2= {(20, 1), (20, 2), (20, 4), (20, 5), (20, 10), (20, 20), (19, 19), (19, 1), (18, 1), (18, 2), (18, 3), (18, 6), (18, 9), (18, 18), (17, 1), (17, 17), (16, 1), (16, 2), (16, 4), (16, 8), (16, 16), (15, 1), (15, 3), (15, 5), (15, 15), (14, 1), (14, 2), (14, 7), (14, 14), (13, 1), (13, 13), (12, 1), (12, 2), (12, 3), (12, 4), (12, 6), (12, 12), (11, 1), (11, 11), (10, 1), (10, 2), (10, 5), (10, 10), (9, 1), (9, 3), (9, 9), (8, 1), (8, 2), (8, 4), (8, 8), (7, 1), (7, 7), (6, 1), (6, 2), (6, 3), (6, 6), (5, 1), (5, 5), (4, 1), (4, 2), (4, 4), (3, 1), (3, 3), (2, 1), (2, 2), (1, 1)}

R1R2 = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), (7, 7), (8, 8), (9, 9), (10, 10), (11, 11), (12, 12), (13, 13), (14, 14), (15, 15), (16, 16), (17, 17), (18, 18), (19, 19), (20, 20)}

Number of elements in R1-R2=66-20=46 elements.

 



Q 27 :

The number of symmetric relations defined on the set {1, 2, 3, 4} which are not reflexive is _______.    [2024]



(960)

Let A = {1, 2, 3, 4}

n(A)=4

  Number of reflexive and symmetric relation =2n2-n2=26

Number of symmetric relations =2n(n+1)2=210

 Number of relations which is symmetric but not reflexive =210-26=1024-64=960

 



Q 28 :

Let A = {1, 2, 3, 4} and R = {(1, 2), (2, 3), (1, 4)} be a relation on A. Let S be the equivalence relation on A such that RS and the number of elements in S is n. Then, the minimum value of n is ________.         [2024]



(16)

Given A = {1, 2, 3, 4}

R = {(1, 2), (2, 3), (1, 4)}

S to be equivalence, it should be reflexive, symmetric and transitive.

For reflexive add (1, 1), (2, 2), (3, 3), (4, 4).

For symmetric add (2, 1), (3, 2), (4, 1).

For transitive (1, 2), (2, 3)  (1, 3), so add (1, 3) also add (3, 1) for symmetric

and (4, 1), (1, 2)  (4, 2), so add (4, 2) also add (2, 4) for symmetric.

∴ S = {(1, 2), (2, 3), (1, 4), (1, 1), (2, 2), (3, 3), (4, 4), (2, 1), (3, 2), (4, 1), (3, 1), (1, 3), (2, 4), (4, 2), (3, 4), (4, 3)}

∴ n(S) = 16



Q 29 :

Let A = {1, 2, 3, ..........., 100}. Let R be a relation on A defined by (x, y) ∈ R if and only if 2x = 3y. Let R1 be a symmetric relation on A such that RR1 and the number of elements in R1 is n. Then, the minimum value of n is ______.            [2024]

 



(66)

We have, A = {1, 2, 3, ..., 100}

R = {(3, 2), (6, 4), (9, 6), (12, 8), ....(99, 66)}

n(R) = 33

Since, R1 is symmetric and RR1

∴ n(R1) = 66

 



Q 30 :

Let A be the set of all functions f : Z  Z and R be a relation on A such that R = {(f, g) : f(0) = g(1) and f(1) = g(0)}. Then R is :          [2025]

  • Transitive but neither reflexive nor symmetric.

     

  • Symmetric and transitive but not reflexive.

     

  • Symmetric but neither reflexive nor transitive.

     

  • Reflexive but neither symmetric nor transitive.

     

(3)

We have, R = {(f, g) : f(0) = g(1) and f(1) = g(0)}

For reflexive: (f, f R

  f(0) = f(1) must hold f

But f(0)  f(1)

Therefore, R is not reflexive.

For symmetric: If (f, g R  (g, f R

Now, g(0) = f(1) and g(1) = f(0), which is true f

  R is symmetric

For transitive : IF (f, g R and (g, h R  (f, h R

Now, (f, g R  f(0) = g(1) and f(1) = g(0)

          (g, h R  g(0) = h(1) and g(1) = h(0)

For (f, h R, we need f(0) = h(1) and f(1) = h(0)

But, f(0) = g(1) = h(0)  h(1) and f(1) = g(0) = h(1)  h(0)

Hence, R is not transitive.