Q 1 :    

While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is 1 mm and circular scale reading is equal to 42 divisions. Pitch of screw gauge is 1 mm and it has 100 divisions on circular scale. The diameter of the wire is x50 mm. The value of x is            [2024]

  • 142

     

  • 21

     

  • 42

     

  • 71

     

(D)          MSR = 1 mm, CSR = 42, pitch = 1 mm

               LC=pitchNo. of CSD=(1100)=0.01mm

               Reading by screw gauge = Main scale reading + Least count × circular scale reading

                Diameter = MSR + LC × CSD = 1 mm + 0.1 mm × 42 = 1.42 mm

                Diameter = 1.42 mm = x50x=71



Q 2 :    

There are 100 divisions on the circular scale of a screw gauge of pitch 1 mm. With no measuring quantity in between the jaws, the zero of the circular scale lies 5 divisions below the reference line. The diameter of a wire is then measured using this screw gauge. It is found that 4 linear scale divisions are clearly visible while 60 divisions on circular scale coincide with the reference line. The diameter of the wire is           [2024]

  • 4.60 mm

     

  • 3.35 mm

     

  • 4.65 mm

     

  • 4.55 mm

     

(D)         Pitch P = 1 mm, N = 100

              least count C=PN=1mm100=0.01mm

              The instrument has a positive zero error.

              e=NC=5×0.01=0.05mm

             Main scale reading is 4 ×(mm) = 4 mm

             Circular scale reading is 60 ×0.01 = 0.6 mm

             Observed reading is R0 = 4 + 0.6 = 4.6 mm

             So True reading R0-e = 4.6 - 0.05 = 4.55 mm