Q 1 :    

Average force exerted on a non-reflecting surface at normal incidence is 2.4×10-4N. If 360 W.Cm2 is the light energy flux during span of 1 hour 30 minutes, Then the area of the surface is             [2024]

  • 0.02 m2

     

  • 0.2 m2

     

  • 20 m2

     

  • 0.1 m2

     

(A)         Radiation force,F=IAcA=FcI

              A=2.4×10-4×3×108360×104=2.4120=0.02m2

 



Q 2 :    

An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity 6×108W/m2 falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space =3×108m/s)                 [2024]

  • 36Nm-2

     

  • 18Nm-2

     

  • 6Nm-2

     

  • 2Nm-2

     

(C)        Radiation pressure=IV

                                                   =I·μc=6×108×33×108=6N/m2

 



Q 3 :    

Two sources of light emit with a power of 200 W. The ratio of the number of photons of visible light emitted by each source having wavelengths 300 nm and 500 nm respectively, will be               [2024]

  • 3 : 5

     

  • 1 : 5

     

  • 5 : 3

     

  • 1 : 3

     

(A)      Let n1 and n2 are number of photons emitted by sources per second.

            n1×hcλ1=200

           n2×hcλ2=200

           n1n2=λ1λ2=300500=35

 



Q 4 :    

Monochromatic light of frequency 6×1014Hz is produced by a laser. The power emitted is 2×10-3W. How many photons per second, on an average, are emitted by the source?               [2024]

(Given h=6.63×10-34 Js)

  • 9×1018

     

  • 6×1015

     

  • 5×1015

     

  • 7×1016

     

(C)          Power P=2×10-3W

                Energy E=hν=6.63×10-34×6×1014

                 n=PE=2×10-36.63×10-34×6×1014

                n=5×1015

 



Q 5 :    

In the Franck-Hertz experiment, the first dip in the current-voltage graph for hydrogen is observed at 10.2 V. The wavelength of light emitted by the hydrogen atom when excited to the first excitation level is ___ nm.

(Given hc=1245eVnm, e=1.6×10-19C)                [2024]



(122)            10.2eV=hcλλ=1245 eV-nm10.2eV=122.06nm