Chemical Equilibrium | JEE Main Chemistry Chapter Wise Question Papers

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(B) ${Fe}_{2} O_{3} (s) + 3 CO (g) ⇌ Fe (l) + 3 {CO}_{2} (g)$

$K_{c} = \frac{{[{CO}_{2}]}^{3}}{{[CO]}^{3}}$

$F e_{2} O_{3} (s)$ do not affect the equilibrium. Hence addition or removal of $F e_{2} O_{3} (s)$ or $F e (l)$ do not affect the equilibrium.

(37)

$Δ G ° = Δ H ° - T Δ S °$

$Δ G ° = 77.2 kJ {mol}^{- 1} - 400 K \times 122 {JK}^{- 1}$

$= 77.2 \times 1000 {Jmol}^{- 1} - 400 K \times 122 {JK}^{- 1}$

$= 28400 J {mol}^{- 1}$

$- 2.303 RT \log_{10} K = ΔG °$

$- 2.303 RT \log_{10} K_{eq} = 28400 J {mol}^{- 1}$

$- 2.303 \times 8.314 J {mol}^{- 1} K^{- 1} \times 400 K \times \log_{10} K_{eq} = 28400 J {mol}^{- 1}$

$\log_{10} K_{e q} = - 3.7 = - 37 \times 10^{- 1}$

(57)

$ΔG ° = - 2.303 RT \log_{10} K$

$=-2.303×8.314 J {mol}^{- 1} K^{- 1} \times 300 K \log_{10} 10$

$= - 5744.143 J {mol}^{- 1}$

$= - 5.744 kJ {mol}^{- 1} \approx - 57 \times 10^{- 1} kJ {mol}^{- 1}$

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