Q 1 :

The following reaction occurs in the Blast furnance where iron ore is reduced to iron metal

Fe2O3(s)+3CO(g)Fe(l)+3CO2(g)

Using the Le-chatelier's principle, predict which one of the following will not disturb the equilibrium.            [2024]

  • Removal of CO

     

  • Addition of Fe2O3

     

  • Removal of CO2

     

  • Addition of CO2

     

(2)         

               Fe2O3(s)+3CO(g)Fe(l)+3CO2(g)

                  Kc=[CO2]3[CO]3

                  Fe2O3(s) do not affect the equilibrium. Hence addition or removal of Fe2O3(s) or Fe(l) do not affect the equilibrium.

 



Q 2 :

For a certain thermochemical reaction MN at T=400KΔH=77.2kJ mol-1,ΔS=122JK-1, log equilibrium constant (logk) is - ______ ×10-1.                 [2024]



(37)

ΔG°=ΔH°-TΔS°

ΔG°=77.2kJ mol-1-400K×122JK-1

         =77.2×1000Jmol-1-400K×122JK-1

         =28400J mol-1

-2.303 RT log10K=ΔG°

-2.303 RT log10Keq=28400Jmol-1

-2.303×8.314Jmol-1K-1×400K×log10Keq=28400Jmol-1

log10Keq=-3.7=-37×10-1



Q 3 :

For a certain reaction at 300K, K = 10, then Go for the same reaction is _________ ×10-1 kJ mol-1. (Given R = 8.314 JK-1 mol-1)              [2024]



(57)

ΔG°=-2.303 RT log10K

         =-2.303×8.314 Jmol-1K-1×300K log1010

         =-5744.143Jmol-1

         =-5.744kJmol-1-57×10-1kJmol-1

 



Q 4 :

Consider the equilibrium

CO(g)+3H2(g)  CH4(g)+H2O(g)

If the pressure applied over the system increases by two fold at constant temperature then

(A) Concentration of reactants and products increases.
(B) Equilibrium will shift in forward directions.
(C) Equilibrium constant increases since concentration of products increase.
(D) Equilibrium constant remains unchanged as concentration of reactants and products remain same.

Choose the correct answer from the options given below:                                           [2025]

  • (A) and (B) only

     

  • (B) and (C) only

     

  • (A), (B) and (C) only

     

  • (A), (B) and (D) only

     

(1)

(A) Since pressure is increased, this means volume has been reduced. If volume is reduced, then concentration of each species (reactants as well as products) in the vessel increases.

(B) On increasing the pressure, system moves in a direction with less number of gaseous moles (Le Chatelier’s principle) which is forward direction in given case.

(C) (D) Equilibrium constant does not change upon changing concentration or pressure of reactants or products.

 



Q 5 :

Given below are two statements:

Statement I: A catalyst cannot alter the equilibrium constant (Kc) of the reaction, temperature remaining constant.

Statement II: A homogenous catalyst can change the equilibrium composition of a system, temperature remaining constant.

In the light of the above statements, choose the correct answer from the options given below.                             [2025]

  • Statement I is false but Statement II is true

     

  • Both Statement I and Statement II are true

     

  • Both Statement I and Statement II are false

     

  • Statement I is true but Statement II is false

     

(4)

A catalyst does not affect the position of equilibrium. It does not affect equilibrium constant or composition of reaction mixture.

 



Q 6 :

In the following system,

PCl5(g)PCl3(g)+Cl2(g) at equilibrium, upon addition of xenon gas at constant T and P, the concentration of               [2025]

  • PCl5 will increase

     

  • Cl2 will decrease

     

  •  PCl5,PCl3 and Cl2 remain constant

     

  • PCl3 will increase

     

(4)

If inert gas is added at constant pressure, then volume of the system increases. This decreases partial pressure of components of the system. To increase the partial pressure, system moves in a direction of more number of gaseous moles i.e. in forward direction.



Q 7 :

The effect of addition of helium gas to the following reaction in equilibrium state, is: PCl5(g)PCl3(g)+Cl2(g)            [2023]

  • Addition of helium will not affect the equilibrium.

     

  • The equilibrium will shift in the forward direction and more of Cl2 and PCl3 gases will be produced.

     

  • The equilibrium will go backward due to suppression of dissociation of PCl5.

     

  • Helium will deactivate PCl5 and reaction will stop.

     

(2)

At constant pressure equilibrium shift where number of moles of gas increases so this reaction goes forward direction.

 



Q 8 :

Water decomposes at 2300 K

H2O(g)H2(g)+12O2(g)

The percent of water decomposing at 2300 K and 1 bar is __________ (Nearest integer).

Equilibrium constant for the reaction is 2×10-3 at 2300 K.                   [2023]



(2)

H2O(g)H2(g)+12O2(g)1-ααα/2

Kp=α(α2)1/21-α=2×10-3

      =(α)3/22(1-α)=2×10-3

     =(α)3/2=22×10-3(α1)

(α)3/2=8×10-3

α=2×10-2

%α=2×10-2×100=2



Q 9 :

At 298 K

N2(g)+3H2(g)2NH3(g),  K1=4×105

N2(g)+O2(g)2NO(g),  K2=1.6×1012

H2(g)+12O2(g)H2O(g),  K3=1.0×10-13

Based on above equilibria, the equilibrium constant of the reaction, 2NH3(g)+52O2(g)2NO(g)+3H2O(g) is ________ ×10-33 (Nearest integer).          [2023]



(4)

Target equation=eq(2)-eq(1)+3eq(3)

K=K2×(K3)3K1=1.6×1012×(1×10-13)34×105

    =16×1011×10-394×105=4×10-33=4



Q 10 :

Consider the following equation:

2SO2(g)+O2(g)2SO3(g),     ΔH=-190 kJ

The number of factors which will increase the yield of SO3 at equilibrium from the following is _______ .

A. Increasing temperature

B. Increasing pressure

C. Adding more SO2

D. Adding more O2

E. Addition of catalyst                                    [2023]



(3)

(i) As reaction is exothermic so on increase in temperature equilibrium shift in backward direction.

(ii) On increasing pressure equilibrium shift in forward direction.

(iii) Addition of catalyst does not affect equilibrium it only increases rate of reaction.