Q 1 :    

A step up transformer is connected to an AC mains supply of 220 V to operate at 11000 V, 88 watt. The current in the secondary circuit, ignoring the power loss in the transformer is             [2024]

  • 8 mA

     

  • 4 mA

     

  • 0.4 A

     

  • 4 A

     

(1)

Given, VP=220 V;  VS=11000 V;  PS=88 W

We know, PS=VSIS

88=11000×IS  or  8811000=IS

  IS=8×10-3A=8 mA



Q 2 :    

In an ideal transformer, the turns ratio is NpNs=12. The ratio Vs:Vp is equal to (the symbols carry their usual meaning)           [2024]

  • 1 : 2

     

  • 2 : 1

     

  • 1 : 1

     

  • 1 : 4

     

(2)

Here, NpNs=12

For ideal transformer, NpNs=VpVs

12=VpVsVsVp=21



Q 3 :    

A 12 V, 60 W lamp is connected to the secondary of a step down transformer, whose primary is connected to ac mains of 220 V. Assuming the transformer to be ideal, what is the current in the primary winding?              [2023]

  • 3.7 A

     

  • 0.37 A

     

  • 0.27 A

     

  • 2.7 A

     

(3)

[IMAGE 263]

Let current in the primary is Ip.

As, the transformer is ideal

   Pi=P0

220×Ip=60

Ip=60220=622=311=0.27 A



Q 4 :    

A step down transformer connected to an AC mains supply of 220 V is made to operate at 11 V, 44 W lamp. Ignoring power losses in the transformer, what is the current in the primary circuit?            [2021]

  • 4 A

     

  • 0.2 A

     

  • 0.4 A

     

  • 2 A

     

(2)

Here, P=44 W, Vp=220 V, Vs=11 V

Power, P=VsIs

44=11×IsIs=4411=4A

Now, VpIp=VsIs

220×Ip=11×4Ip=11×4220=420=0.2 A



Q 5 :    

A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are          [2014]

  • 300 V, 15 A

     

  • 450 V, 15 A

     

  • 450 V, 13.5 A

     

  • 600 V, 15 A

     

(2)

Here, Efficiency of the transformer, η=90%

Input power, Pin=3kW=3×103W=3000W

Voltage across the primary coil, Vp=200V

Current in the secondary coil, Is=6A

As Pin=IpVp

   Current in the primary coil, Ip=PinVp=3000W200V=15A

Efficiency of the transformer,

η=PoutPin=VsIsVpIp    90100=6Vs3000 or Vs=90×3000100×6=450V