Q 1 :    

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): CH2=CH-CH2-Cl is an example of allyl halide.

Reason (R): Allyl halides are the compounds in which the halogen atom is attached to sp2 hybridised carbon atom.

In the light of the above statements, choose the most appropriate answer from the options given below:                [2024]

  • (A) is true but (R) is false

     

  • Both (A) and (R) are true but (R) is not the correct explanation of (A)

     

  • (A) is false but (R) is true

     

  • Both (A) and (R) are true and (R) is the correct explanation of (A)

     

(1)

sp3 carbon next to C=C is called allylic carbon. A halide carrying halogen on allylic carbon is called an allylic halide. CH2=CH-CH2-Cl is hence an allylic halide. Halides containing a halogen atom attached to an sp2 carbon of an aromatic ring are called aryl halides and those containing a halogen atom attached to an sp2 carbon of a C=C bond are called vinyl halides.



Q 2 :    

Which of the following reaction is correct?                          [2024]

  •  

  • C2H5CONH2+Br2+NaOHC2H5CH2NH2+Na2CO3+NaBr+H2O

     

  • CH3CH2CH2NH2 H2OHNO2, 0°CCH3CH2OH+N2+HCl

     

  •  

(4)

 



Q 3 :    

Example of vinylic halide is:                           [2024]

  •  

  •  

  •  

  •  

(1)

C=C carbons are called vinylic carbons. Halides carrying halogen on vinylic carbon are called vinylic halides.

 

 



Q 4 :    

Number of isomeric products formed by monochlorination of 2-methylbutane in presence of sunlight is ______.                    [2024]



(6)

Four structural isomers are possible on monochlorination of 2-methylbutane. Two of these four are formed as enantiomeric pairs. Hence a total of 6 isomers are formed.



Q 5 :    

Total number of isomeric compounds (including stereoisomers) formed by monochlorination of 2-methylbutane is ______.                   [2024]



(6)

Four structural isomers are possible on monochlorination of 2-methylbutane. Two of these four are formed as enantiomeric pairs. Hence, a total of 6 isomers are formed.

 



Q 6 :    

The major products from the following reaction sequence are product A and product B.                               [2024]

The total sum of π electrons in product A and product B are ______. (nearest integer)



(8)

Sum of π electrons in A and B is 4 + 4 = 8.