If all the words with or without meaning made using all the letters of the word "NAGPUR" are arranged as in a dictionary, then the word at position in this arrangement is [2024]
NRAPGU
NRAGPU
NRAPUG
NRAGUP
(A)
Letter in the word NAGPUR = 6
If we fix A _ _ _ _ _
Number of words start with A = 5! = 120
If we fix G _ _ _ _ _
Number of words start with G = 5! = 120
If we fix N A _ _ _ _
Number of words start with NA = 4! = 24
If we fix N G _ _ _ _
Number of words start with NG = 4! = 24
If we fix N P _ _ _ _
Number of words start with NP = 4! = 24
Next word i.e., word in dictionary will be NRAGPU, word will be NRAGUP, word will be NRAPGU.
60 words can be made using all the letters of the word BHBJO, with or without meaning. If these words are written as in a dictionary, then the 50th word is [2024]
OBBJH
HBBJO
OBBHJ
JBBOH
(A)
Let us fix B first (Dictionary Order)
B _ _ _ _ (We have 4 distinct letters left, to be arranged in 4 distinct ways)
Number of ways = 4! = 24
H _ _ _ _ (We have B, B, J, O to be arranged in 4 ways when H is fixed)
Number of ways =
J _ _ _ _ (B, B, H, O to be arranged in 4 ways)
Number of ways =
49th word will be OBBHJ
50th word will be OBBJH
If is the number of ways in which five different employees can sit into four indistinguishable offices where any office may have any number of persons including zero, then is equal to [2024]
43
47
53
51
(D)
Number of ways in which five different employees can sit are
5 0 0 0 5!/5! = 1
4 1 0 0 5!/4! = 5
3 2 0 0 5!/3!2! = 10
3 1 1 0 5!/3! 1! 1! 2! = 10
2 2 1 0
2 1 1 1
Total number of ways =1 + 5 + 10 + 10 + 15 + 10 = 51
Let and Then
and
and
and
and
Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to [2024]
18
15
12
16
(B)
Ways of arranging 8 identical books in 4 identical shelves = {8, 0, 0, 0}, {7, 1, 0, 0}, {6, 2, 0, 0}, {5, 3, 0, 0}, {4, 4, 0, 0}, {6, 1, 1, 0},{5, 2, 1, 0}, {4, 3, 1, 0}, {4, 2, 2, 0}, {3, 3, 2, 0}, {5, 1, 1, 1}, {4, 2, 1, 1}, {3, 3, 1, 1}, {3, 2, 2, 1}, {2, 2, 2, 2}.
Number of ways = 15
[As shelves and books are identical, so the arrangements (5, 2, 1, 0), (2, 5, 1, 0), and (1, 2, 5, 0) are considered as same]
The number of ways of getting a sum 16 on throwing a dice four times is ______. [2024]
(125)
We need sum of 16 on throwing a dice four times so possible ways are:
{(4, 4, 4, 4), (5, 4, 4, 3), (5, 5, 1, 5), (5, 5, 3, 3), (5, 5, 4, 2), (6, 4, 3, 3), (6, 4, 4, 2), (6, 5, 3, 2), (6, 5, 4, 1), (6, 6, 3, 1), (6, 6, 2, 2)}
Obtained Result | Number of Ways |
(6, 6, 2, 2) | |
(6, 6, 3, 1) | |
(6, 5, 4, 1) | |
(6, 5, 3, 2) | |
(6, 4, 4, 2) | |
(6, 4, 3, 3) | |
(5, 5, 4, 2) | |
(5, 5, 3, 3) | |
(5, 5, 1, 5) | |
(5, 4, 4, 3) | |
(4, 4, 4, 4) | |
Total ways | 125 |
The number of integers, between 100 and 1000 having the sum of their digits equals to 14, is ______. [2024]
(70)
Number between 100 to 1000 are 3-digit number.
Let number such that
where and
Case I : All three digits are same ie.,
, which is not possible
Case II : Two digits are same i.e.,
(a, c) = {(3, 8), (4, 6), (5, 4), (6, 2), (7, 0)}
In each subcase, number of ways of forming a 3-digit number =
There are 5 such cases as (a, c) have 5 elements in which 0,7,7 is included
So, total number of 3 digits numbers when 2 digits are same
Case III : All digits are different
(a, b, c) = {(1, 4, 9), (2, 4, 8), (2, 3, 9), (1, 5, 8), (3, 4, 7), (2, 5, 7), (1, 6, 7), (3, 5, 6), (5, 9, 0), (6, 8, 0)}
Total number of 3 digits number formed by above triplet =
Total number of required number = 56 + 14 = 70
All the letters of the word “GTWENTY” are written in all possible ways with or without meaning and these words are written as in a dictionary. The serial number of the word “GTWENTY” is _____. [2024]
(553)
Number of words starts with
Number of words starts with
Number of words starts with
Number of words starts with
Number of words starts with
Number of words starts with
Next word will be GTWENTY
Rank of GTWENTY