All the letters of the word PUBLIC are written in all possible orders and these words are written as in a dictionary with serial numbers. Then the serial number of the word PUBLIC is [2023]
580
582
576
578
(2)
No. of words formed when word starts from B = 5!
No. of words formed when word starts from C = 5!
No. of words formed when word starts from I = 5!
No. of words formed when word starts from L = 5!
No. of words formed when word starts from PB = 4!
No. of words formed when word starts from PC = 4!
No. of words formed when word starts from PI = 4!
No. of words formed when word starts from PL = 4!
No. of words formed when word starts from PUBC = 2!
No. of words formed when word starts from PUBI = 2!
No. of words formed when word starts from PUBLC = 1
Now, the word comes is PUBLIC = 1
∴ Serial number of word PUBLIC
= 4 × 5! + 4 × 4! + 2 × 2! + 1 + 1 = 582
The number of arrangements of the letters of the word "INDEPENDENCE" in which all the vowels always occur together is
14800
16800
18000
33600
The number of ways in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together, is [2023]
(2)

Number of girls = 5
Number of boys = 7
The number of ways of arranging boys around a table is (7 – 1)! = 6!
Now, there are 7 spaces in between two boys, so 5 girls arranged in 7 gaps by ways.
So, required number of ways =
If the number of words, with or without meaning. which can be made using all the letters of the word MATHEMATICS in which C and S do not come together, is (6!)k, then k is equal to [2023]
5670
945
2835
1890
(1)
In the word ''MATHEMATICS'' there are,
Total number of words formed by the letters of the word ''MATHEMATICS'' is
Number of words in which 'C' and 'S' come together is
Then, number of words in which 'C' and 'S' do not come together is
Eight persons are to be transported from city A to city B in three cars of different makes. If each car can accommodate at most three persons, then the number of ways, in which they can be transported, is [2023]
3360
1120
1680
560
(3)
8 persons can be divided into 3 groups of 3, 3, and 2 members each.
If the letters of the word MATHS are permuted and all possible words so formed are arranged as in a dictionary with serial numbers, then the serial number of the word THAMS is [2023]
103
104
101
102
(1)
Given word is MATHS.
In alphabetical order: A, H, M, S, T
Now, word starting with
A_ _ _ _ i.e., 4! ; H_ _ _ _ i.e., 4!
M_ _ _ _ i.e., 4! ; S_ _ _ _ i.e., 4!
T A_ _ _ i.e., 3! ; T H A M S i.e., 1
The number of five digit numbers, greater than 40000 and divisible by 5, which can be formed using the digits 0, 1, 3, 5, 7 and 9 without repetition, is equal to [2023]
132
120
72
96
(2)
Numbers greater than 40000 and divisible by 5 can be formed using digits 0, 1, 3, 5, 7, 9 in the following ways:
| Number of ways | |
|---|---|
| 5 _ _ _ 0 | 4 × 3 × 2 × 1 = 24 |
| 7 _ _ _ 0 | |
| 7 _ _ _ 5 | 4 × 3 × 2 × 2 = 48 |
| 9 _ _ _ 0 | |
| 9 _ _ _ 5 | 4 × 3 × 2 × 2 = 48 |
Total number of ways = 24 + 48 + 48 = 120
All words, with or without meaning, are made using all the letters of the word MONDAY. These words are written as in a dictionary with serial numbers. The serial number of the word MONDAY is [2023]
327
328
326
324
(1)
Given, A, D, M, N, O, Y
A → 5! ; D → 5! ; M A → 4! ; M N → 4!
M O A → 3! ; M O D → 3! ; M O N A → 2! ; M O N D A Y
⇒ Rank = 2(5)! + 3(4)! + 2(3)! + 2! + 1
= 240 + 72 + 12 + 2 + 1 = 327
The total number of three-digit numbers, divisible by 3, which can be formed using the digits 1, 3, 5, 8, if repetition of digits is allowed, is [2023]
18
21
22
20
(3)
Case I: All the three digits are same i.e., 111, 333, 555, 888. All the numbers are divisible by 3.
Case II: Two digits are same.
We can see that when two digits are same, then numbers having digits 5, 5, 8 or 8, 8, 5 will be divisible by 3 as their sum is divisible by 3.
Now, for each number, we have arrangements.
In this case, we have 6 numbers divisible by 3.
Case III: All digits are distinct.
i.e., (1, 3, 5), (1, 3, 8)
So, number formed = 2 × 3! = 12
Hence, total 3-digit numbers formed by digits 1, 3, 5, 8 and divisible by 3 is 4 + 6 + 12 = 22.
The number of square matrices of order 5 with entries from the set {0, 1}, such that the sum of all the elements in each row is 1 and the sum of all the elements in each column is also 1, is [2023]
225
120
125
150
(2)
In first column, 1 can be placed in any of the 5 places = 5
In second column, 1 can be placed in any of the 4 places = 4
In third column, 1 can be placed in any of the 3 places = 3
In fourth column, 1 can be placed in any of the 2 places = 2
In fifth column, 1 can be placed in any of the 1 place = 1
Required number of ways = 5 × 4 × 3 × 2 × 1 = 120
The number of integers, greater than 7000 that can be formed, using the digits 3, 5, 6, 7, 8 without repetition, is [2023]
168
120
220
48
(1)
5 digits numbers = 5! = 120
Four digit number greater than 7000 = 2 × 4 × 3 × 2 = 48
Total number greater than 7000 = 120 + 48 = 168
The number of numbers, strictly between 5000 and 10000 can be formed using the digits 1, 3, 5, 7, 9 without repetition, is [2023]
72
120
6
12
(1)
Number of numbers lies between 5000 and 10000 are 4 digit numbers greater than 5000 so, the first digit can be filled in 3 ways (using 5, 7, 9) and as repetition is not allowed, the other choices are 4, 3, 2.
Total number of number = 3 × 4 × 3 × 2 = 72
The letters of the word OUGHT are written in all possible ways and these words are arranged as in a dictionary, in a series. Then the serial number of the word TOUGH is [2023]
86
89
79
84
(2)
The letters in sequence of the word ‘OUGHT’ in alphabetical order as follows: G, H, O, T, U
Word starts with G can arrange in 4! ways.
H can arrange in 4! ways.
O can arrange in 4! ways.
TG can arrange in 3! ways.
TH can arrange in 3! ways.
TOG can arrange in 2! ways.
TOH can arrange in 2! ways.
TOUGH can arrange in 1! way.
So we must have serial number of the word is 89.
The number of 3 digit numbers, that are divisible by either 3 or 4 but not divisible by 48, is [2023]
400
507
432
472
(3)
We know that we have total 3-digit numbers only 900.
Out of these 900, the number divisible by 3
In the same way, the numbers divisible by 4
So, divisible by 3 and 4 = 75
Number divisible by either 3 or 4
Now, we have to remove the numbers divisible by 48, 144, 192 ....... 18 terms.
Hence, required numbers, who are divisible by either 3 or 4 but not by 48 is
The number of ways of selecting two numbers and and such that 2 is the remainder when is divided by 23 is [2023]
54
108
268
186
(2)
The number of permutations, of the digits 1, 2, 3, ..., 7 without repetition, which neither contain the string 153 nor the string 2467, is ________ . [2023]
(4898)
Given digits are 1, 2, 3, 4, 5, 6, 7
Total number of permutations = 7!
Let A = number of numbers containing string 153
Let B = number of numbers containing string 2467
Required number of permutations = Total number of permutations -
The sum of all the four-digit numbers that can be formed using all the digits 2, 1, 2, 3 is equal to _________ . [2023]
(26664)
Sum of all unit place numbers
In an examination, 5 students have been allotted their seats as per their roll numbers. The number of ways, in which none of the students sits on the allotted seat, is __________ . [2023]
(44)
Dearrangement of 5 students
The number of seven digit positive integers formed using the digits 1, 2, 3 and 4 only and sum of the digits equal to 12 is __________ . [2023]
(413)
Case 1:
Number of ways = [Since, 1 repeats five times]
Case 2:
Number of ways = [Since, 1 repeats 4 times and 3 repeats 2 times]
Case 3:
Number of ways = [Since, 2 repeats 3 times and 1 repeats 3 times]
Case 4:
Number of ways = [Since, 2 repeats 5 times and 1 repeats 2 times]
Case 5:
Number of ways = [Since, 1 repeats 4 times and 2 repeats 2 times]
Total numbers of 3-digit numbers that are divisible by 6 and can be formed by using the digits 1, 2, 3, 4, 5 with repetition, is ________ . [2023]
(16)
Total 3-digit numbers formed by 1, 2, 3, 4, 5 when the last digit in 4 and divisible by 6.

When last digit is 2:

A person forgets his 4-digit ATM pin code. But he remembers that in the code all the digits are different, the greatest digit is 7 and the sum of the first two digits is equal to the sum of the last two digits.Then the maximum number of trials necessary to obtain the correct code is _____ . [2023]
(72)

Sum of first two digits
Sum of last two digits =
Case–I : = 7
2 × 12 = 24 ways.

2 × 8 ways = 16 ways

2 × 4 ways = 8 ways
Total ways = 24 + 16 + 16 + 8 + 8 = 72
The number of 3-digit numbers, that are divisible by either 2 or 3 but not divisible by 7, is ___________ . [2023]
(514)
Number of numbers divisible by 2 = 450
Number of numbers divisible by 3 = 300
Number of numbers divisible by 7 = 128
Number of numbers divisible by 2 & 7 = 64
Number of numbers divisible by 3 & 7 = 43
Number of numbers divisible by 2 & 3 = 150
Number of numbers divisible by 2, 3 & 7 = 21
Total numbers = 450 + 300 – 150 – 64 – 43 + 21 = 514
The number of words, with or without meaning, that can be formed using all the letters of the word ASSASSINATION so that the vowels occur together, is __________ . [2023]
(50400)
In the word ASSASSINATION, there are 6 vowels A A A I I O and consonants S S S S N N T.
The total number of six digit numbers, formed using the digits 4, 5, 9 only and divisible by 6, is ________ . [2023]
(81)
Total number of 6-digit numbers formed by the digits 4, 5, 9 and divisible by 6 is when all the digits are same.
The number of 9 digit numbers, that can be formed using all the digits of the number 123412341 so that the even digits occupy only even places, is __________ . [2023]
(60)
Even numbers are 2, 4, 2, 4
Odd numbers are 1, 3, 1, 3, 1
Let and be distinct integers where and Then, the number of ways of choosing and such that is divisible by 5, is _________ . [2023]
(120)
Let
Possible cases are
Five digit numbers are formed using the digits 1, 2, 3, 5, 7 with repetitions and are written in descending order with serial numbers. For example, the number 77777 has serial number 1. Then the serial number of 35337 is _______ . [2023]
(1436)
The total number of 4-digit numbers whose greatest common divisor with 54 is 2, is _________ . [2023]
(3000)
Number of 4-digit numbers (the repetition of digits is allowed) which are made using the digits 1, 2, 3 and 5, and are divisible by 15, is equal to ______ . [2023]
(21)
| x | y | z | 5 |
Let where and . Then is equal to ________ . [2023]
(26)
We have,