ldentify the logic gate given in the circuit [2024]

NOR gate
NAND gate
OR gate
AND gate
(3)

Y = A + B, Hence OR gate
Following gates section is connected in a complete suitable circuit.

For which of the following combination, bulb will glow (ON) [2024]
A = 0, B = 0, C = 0, D = 1
A = 1, B = 1, C = 1, D = 0
A = 1, B = 0, C = 0, D = 0
A = 0, B = 1, C = 1, D = 1
(3)
Bulb is only on when across the bulb, signals are opposite → 0,1 or 1,0
A → Signals are 0 and 0
B → Signals are 1 and 1
C → Signals are 0 and 1
D → Signals are 0 and 0
So, the bulb is on only in option C.
The output (Y) of logic circuit given below is 0 only when [2024]

A = 1, B = 0
A = 0, B = 0
A = 0, B = 1
A = 1, B = 1
(2)

The correct truth table for the following logic circuit is: [2024]

| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
(2)
By Boolean expression
| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
The output Y of following circuit for given inputs is [2024]

(3)


In the truth table of the above circuit, the values of X and Y are [2024]
1, 1
1, 0
0, 1
0, 0
(1)
For

For

The truth table of the given circuit diagram is : [2024]

| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
(2)

This is XOR gate
Identify the logic operation performed by the given circuit. [2024]

AND
NOR
NAND
OR
(4)

The truth table for this given circuit is [2024]

| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
(3)

The output of the given circuit diagram is [2024]

| A | B | Y |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 0 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 1 | 0 |
(3)

The output of the circuit is low (zero) for: [2025]

(A) X = 0, Y = 0 (B) X = 0, Y = 1
(C) X = 1, Y = 0 (D) X = 1, Y = 1
Choose the correct answer from the options given below:
(A), (C) and (D) only
(A), (B) and (C) only
(B), (C) and (D) only
(A), (B) and (D) only
(3)

| X | Y | |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
Which of the following circuits has the same output as that of the given circuit? [2025]





(1)


For the circuit shown above, equivalent GATE is: [2025]
OR gate
NOT gate
AND gate
NAND gate
(1)
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
OR Gate
The truth table for the circuit given below is: [2025]

| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
| 0 | 1 | 1 |
| A | B | Y |
| 0 | 0 | 0 |
| 1 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 1 | 0 |
| A | B | Y |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
(1)

XOR (Exclusive OR)
In the digital circuit shown in the figure, for the given inputs the P and Q values are: [2025]

P = 1, Q = 1
P = 0, Q = 0
P = 0, Q = 1
P = 1, Q = 0
(2)

Choose the correct logic circuit for the given truth table having inputs A and B. [2025]
| Inputs | Output | |
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |




(2)
Option 2 matches the truth table
The truth table corresponding to the circuit given below is [2025]

| A | B | C |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 1 | 1 |
| A | B | C |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
| A | B | C |
| 0 | 0 | 1 |
| 1 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 1 | 0 |
| A | B | C |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
(2)

| A | B | A + B | C |
| 0 | 0 | 0 | 0 |
| 1 | 0 | 1 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 1 | 1 | 1 |
The Boolean expression can be realised with which of the following gate configurations. [2025]
A. One 3-input AND gate, 3 NOT gates and one 2-input OR gate, one 2-input AND gate
B. One 3-input AND gate, 1 NOT gate, one 2-input NOR gate and one 2-input OR gate
C. 3-input OR gate, 3 NOT gates and one 2-input AND gate
Choose the correct answer from the options given below:
B, C only
A, B only
A, B, C only
A, C only
(2)

Consider the following logic circuit. [2025]

The output is Y = 0 when:
A = 1 and B = 1
A = 0 and B = 1
A = 1 and B = 0
A = 0 and B = 0
(1)

| A | B | Y |
| 0 | 0 | 1 |
| 1 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 1 | 0 |
The logic gate equivalent to the given circuit diagram is [2023]

NOR
NAND
OR
AND
(2)
NAND gate
For the given logic gates combination, the correct truth table will be [2023]

| A | B | X |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 0 |
| A | B | X |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| A | B | X |
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| A | B | X |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
(2)

The output waveform of the given logical circuit for the following inputs A and B as shown below is [2023]





(4)

The output Y for the inputs A and B of the circuit is given by

Truth table of the shown circuit is: [2023]




(4)

Name the logic gate equivalent to the diagram attached [2023]

OR
AND
NAND
NOR
(4)
Circuit is closed when neither A nor B is closed ⇒ current flows for A = 0 B = 0 when either or both of A & B is closed we get current bypass from switch
Hence it is “NOR” gate
For the logic circuit shown, the output waveform at Y is ________ [2023]





(1)
| A | B | Y |
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
According to truth table, resultant graph is

The logic performed by the circuit shown in figure is equivalent to [2023]

AND
NAND
OR
NOR
(1)

The truth table for the given circuit will be:
| a | b | output |
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
Hence it will be equivalent to AND gate.
The logic operations performed by the given digital circuit is equivalent to [2023]

AND
NOR
OR
NAND
(1)

For the following circuit and given inputs A and B, choose the correct option for output ‘Y’ [2023]





(4)

The output from a NAND gate having inputs A and B given below will be. [2023]





(1)
Truth table for NAND gate is
| A | B | |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
On the basis of given input A and B the truth table is
| A | B | Y |
| 1 | 1 | 0 |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
| 0 | 0 | 1 |
| 0 | 1 | 1 |
So the correct answer is Option 1.
The given circuit works as : [2026]

NOR gate
OR gate
AND gate
NAND gate
(4)
