Electronic Devices | Physics JEE previous year questions with Solutions

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Topic Question Set

Q 1 :
The acceptor level of a p-type semiconductor is 6 eV. The maximum wavelength of light which can create a hole would be (Given hc = 1242 eVnm.) [2024]

407 nm
207 nm
103.5 nm
414 nm

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(B) $Energy = \frac{h c}{λ};$

$E = \frac{1242}{λ (nm)} eV \Rightarrow 6 = \frac{1242}{λ (nm)}$

$\Rightarrow λ = \frac{1240}{6} = 207 nm$

Q 2 :
A light emitting diode (LED) is fabricated using GaAs semiconducting material whose band gap is 1.42 eV. The wavelength of light emitted from the LED is: [2024]

650 nm
1243 nm
875 nm
1400 nm

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(C) $λ (nm) = \frac{1240}{E (eV)}$

$λ = \frac{1240}{1.42} = 875 nm (a pprox .)$

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