Which figure shows the correct variation of applied potential difference (V) with photoelectric current (i) at two different intensities of light () of same wavelengths? [2024]
(1)
Saturation current depends on intensity of incident light.
Also, according to question, both have same wavelength.
Hence stopping potential will remain same, it means will be same.
Since , hence saturation current corresponding to will be greater than that corresponding to .
Given below are two statements:
Statement I: Figure shows the variation of stopping potential with frequency (ν) for the two photosensitive materials and . The slope gives value of , where h is Planck’s constant, e is the charge of an electron.
Statement II: will emit photoelectrons of greater kinetic energy for the incident radiation having the same frequency.
In the light of the above statements, choose the most appropriate answer from the options given below. [2024]
Statement I is incorrect but Statement II is correct
Both Statement I and Statement II are incorrect
Both Statement I and Statement II are correct
Statement I is correct and Statement II is incorrect
(4)
slope =
Work function of is higher than so kinetic energy of emitted electron is less for
For the photoelectric effect, the maximum kinetic energy () of the photoelectrons is plotted against the frequency () of the incident photons as shown in the figure. The slope of the graph gives [2024]
Ratio of Planck’s constant to electric charge
Work function of the metal
Charge of electron
Planck’s constant
(4)
We know that
Slope of kinetic energy versus frequency curve will be equal to slope