Q 1 :    

A pole 6m high is fixed on the top of a tower. The angle of elevation of the top of the pole observed from a point P on the ground is 60o and the angle of depression of the point P from the top of the tower is 45o. Find the height of the tower and the distance of point P from the foot of the tower. (Use 3 = 1.73)



(8.19)

Let BC be the pole and AB be the tower of height ‘h’ m.

tan45°=1=hx

h=x  ---- (i)

tan60°=3=h+6x

h+6=x3  ---- (ii)

Solving (i) & (ii) to get

h=3(3+1)=8.19

and x=8.19

Therefore, the height of tower is 8.19 m and the distance of point P from the foot of the tower is 8.19 m