Q 1 :

Two circles touch each other externally at C and AB is common tangent of circles, then ACB is

  • 70°

     

  • 60°

     

  • 100°

     

  • 90°

     

(4)

Draw CM perpendicular to AB.

Now, AM = MC and MB = MC (tangents drawn from external point are equal).

⇒ AM = MC

MAC = MCA = 45°

(Since Δ AMC is right triangle)

∴  Also, MB = MC ⇒ MBC = MCB = 45° (Since Δ MBC is right angle triangle)

ACB = MCA + MCB = 45° + 45° = 90° ⇒ ACB = 90°



Q 2 :

If the circumference of a circle and the perimeter of a square are equal, then

  • Area of the circle = Area of the square

     

  • Area of the circle > Area of the square

     

  • Area of the circle < Area of the square

     

  • Nothing definite can be said about the relation between the areas of the circle and square.

     

(2)

Area of the circle > Area of the square

 



Q 3 :

The area of the circle that can be inscribed in a square of 6cm is

  • 36π cm2

     

  • 18π cm2

     

  • 12π cm2

     

  • 9π cm2

     

(4)

ABCD is a square of side 6 cm. PQ is a diameter of the given circle such that PQ=AB=6cm

 Radius (r)=62=3 cm

Area of the circle=πr2=π(3)2=9π cm2.

 



Q 4 :

If two tangents inclined at an angle of 60o are drawn to a circle of radius 3cm, then the length of each tangent is equal to

  • 33/2cm

     

  • 3cm

     

  • 6cm

     

  • 33cm

     

(4)

Angle between two tangents = 60°     (given)

  Tangents are equally inclined to each other

  OPA=OPB=30°

and OAP=90°

(Tangent is perpendicular to the radius)

In PAO, tan30°=OAAP13=3APAP=33

Hence, the length of each tangent is 33 cm



Q 5 :

In the given figure, tangents PA and PB to the circle centred at O, from point P are perpendicular to each other. If PA = 5 cm, then length of AB is equal to

  • 5 cm

     

  • 52 cm

     

  • 25 cm

     

  • 10 cm

     

(2)

PA = PB (Tangents from an external point P)

APB is a Right angle Triangle

AB2=AP2+PB2  [AP = PB]

AB2=2AP2

AB2=2×52

AB=52 cm

 



Q 6 :

In the given figure, PA and PB are two tangents drawn to the circle with centre O and radius 5 cm. If APB=60°, then the length of PA is :

  • 5/3cm

     

  • 53cm

     

  • 10/3cm

     

  • 10cm

     

(2)      53cm

 



Q 7 :

AB and CD are two chords of a circle intersecting at P. Choose the correct statement from the following:

  • ADP~CBA

     

  • ADP~BPC

     

  • ADP~BCP

     

  • ADP~CBP

     

(4)

APD=CPB [vertically opposite angle]

ADP=CBP [Angle subtends on the same segment]

ADP~CBP (by AA similarity)

 



Q 8 :

In the given figure, AT is tangent to a circle centred at O. If CAT=40°, then CBA is equal to

  • 70°

     

  • 50°

     

  • 65°

     

  • 40°

     

(4)

Given, CAT=40°

BAT=90°

BAC+CAT=90°

BAC=50°

ACB=90°  [Angle in semi-circle]

In ABC, A+B+C=180°

50°+B+90°=180°

B=180°-140°=40°

 



Q 9 :

Maximum number of common tangents that can be drawn to two circles intersecting at two distinct points is:

  • 4

     

  • 3

     

  • 2

     

  • 1

     

(3)

The maximum number of common tangents that can be drawn to two circles intersecting at two distinct points is 2, as shown in

 



Q 10 :

In Fig, O is the centre of the circle. MN is the chord and the tangent ML at point M makes an angle of 70° with MN. The measure of ∠MON is:

  • 120°

     

  • 140°

     

  • 70°

     

  • 90°

     

(2)

As ML is tangent at M and OM is radius of the circle, therefore ∠OML = 90°

⇒ ∠OMN + ∠NML = 90°
⇒ ∠OMN + 70° = 90° ⇒ ∠OMN = 20°

In ΔOMN, we have OM = ON (? radii of circle)
⇒ ∠OMN = ∠ONM = 20° (Angles opposite to equal sides are equal)

Also, ∠OMN + ∠MON + ∠ONM = 180°
⇒ 20° + ∠MON + 20° = 180°
⇒ ∠MON = 180° – 40° = 140°