In an A.P., if the first term a = 7, nth term an 84 and the sum of first n terms = 2093/2, then n is equal to:
22
24
23
26
(3)
Which term of the A.P. –29, –26, –23, ..., 61 is 16?
11th
16th
10th
31st
(2)
Given,
Here we know,
The 7th term from the end of the A.P. : – 8, – 5, – 2, ..., 49 is :
67
13
31
10
(3) 31
If k + 7, 2k – 2 and 2k + 6 are three consecutive terms of an A.P., then the value of k is :
15
17
5
1
(2) 17
The common difference of an A.P. in which a15 – a11 = 48, is
12
16
–12
–16
(1)