The sum of the lower limit of median class and the upper limit of the modal class of the following data is:
Marks | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
No. of students | 8 | 10 | 12 | 22 | 30 | 18 |
70
80
90
100
(2) 80
For the following distribution:
Class | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 |
Frequency | 10 | 15 | 12 | 20 | 9 |
the sum of lower limits of the median class and modal class is
15
25
30
35
(2)
Class | Frequency (f) | c.f. |
0 - 5 | 10 | 10 |
5 - 10 | 15 | 25 |
10 - 15 | 12 | 37 |
15 - 20 | 20 | 57 |
20 - 25 | 9 | 66 |
N = 66 |
Since, then
and cumulative frequency greater than or equal to 33 lies in class 10 – 15
So, median class is 10 – 15
Lower limit of median class is 10
and highest frequency is 20 lie in class 15 – 20
So, modal class is 15 – 20.
Lower limit of modal class is 15.
Hence, sum of lower limits of the median and modal class is 10 + 15 = 25.
If the difference of Mode and Median of a data is 24, then the difference of median and mean is
8
12
24
36
(2)
mode – median = 24 (given)
mode = 24 + median
Since, mode = 3 median – 2 mean [By empirical relation]
24 + median = 3 median – 2 mean
⇒ 2 median – 2 mean = 24
⇒ median – mean = 12
The middle most observation of every data arranged in order is called
mode
median
mean
deviation
(2)
The middle most observation, after arranging all observations in ascending or descending order is called the median.
For some data with respective frequencies , the value of is equal to:
(4) 0
After an examination, a teacher wants to know the marks obtained by maximum number of the students in her class. She requires to calculate ................. of marks.
median
mode
mean
range
(2)
Mode = The Most Common or (Maximum). Number that appears in your set of data.
If value of each observation in a data is increased by 2, then median of the new data
increases by 2
increases by 2n
remains same
decreases by 2
(1)
When value of each observation in data is increased by 2.
So, median of data is Increases by 2