Q 1 :    

The pair of linear equations 2x + 3y = 5 and 4x + 6y = 10 is

  • inconsistent

     

  • consistent

     

  • dependent consistent

     

  • none of these

     

(3)

Dependent Consistent

 



Q 2 :    

If the system of equations 3x+y=1 and (2k-1)x+(k-1)y=2k+1 is inconsistent, then k =

  • -1

     

  • 0

     

  • 1

     

  • 2

     

(4)

3x+y=1   ...(i)

and (2k-1)x+(k-1)y=2k+1 ...(ii)

Comparing eq. (i) with a1x+b1y+c1=0 and eq. (ii)

with a2x+b2y+c2=0, we get

a1=3,  a2=2k-1,  b1=1,  b2=k-1,  c1=-1 and c2=-(2k+1)

Since, system is inconsistent, then a1a2=b1b2c1c2

32k-1=1k-1-1-(2k+1)32k-1=1k-1 or 1k-112k+1

3k-3=2k-1 or 2k+1k-1k=2 or k-2

Hence, the value of k is 2.

 



Q 3 :    

In the given figure, graphs of two linear equations are shown. The pair of these linear equations is:

  • consistent with unique solution.

     

  • consistent with infinitely many solutions.

     

  • inconsistent.

     

  • inconsistent but can be made consistent by extending these lines.

     

(4)    inconsistent but can be made consistent by extending these lines.

 



Q 4 :    

The pair of equations x = 2a and y = 3b (a,b0) graphically represents straight lines which are :

  • coincident

     

  • parallel

     

  • intersecting at (2a, 3b)

     

  • intersecting at (3b, 2a)

     

(3)     intersecting at (2a, 3b)

 



Q 5 :    

The value of k for which the system of equations 3x – y + 8 = 0 and 6x – ky + 10 = 0 has infinitely many solutions, is

  • – 2

     

  • 2

     

  • 1/2

     

  • − 1/2

     

(2)

Given equation are 3x-y+8=0 and 6x-ky+16=0

Here, a1=3, b1=-1, c1=8

a2=6, b2=-k, c2=16

For Infinite many solution, a1a2=b1b2=c1c236=-1-k=8161k=12k=2

 



Q 6 :    

Consider the equation changes from y = 3x + 7 to y = 3x − 4. What is true about the changes to the graph?
(i) The coefficient of x remains same.
(ii) The value of y at x = 0 decreases.
(iii) Both lines are on the same side of the origin.
(iv) The line shifts downward.

  • (i), (iii) and (iv)
     

  • (ii) and (iv) only

     

  • (i), (ii) and (iv)

     

  • (i), (ii), (iii) and (iv)

     

(3)

When the equation changes from y = 3x + 7 to y = 3x − 4, the graph changes as shown in the figure.

(i) Yes, the coefficient of x i.e., 3 remains same.
(ii) The value of y at x = 0 decreases from 7 to −4.
(iii) Clearly, both lines are on the opposite side of the origin.
(iv) Yes, the line shifts downward.

 



Q 7 :    

Consider the lines given by the equations y = (1/3)x + 5 and y = (1/3)x − 2. Which of the following statements are true regarding these lines?

 

(i) They intersect in 1st quadrant.
(ii) They are parallel to each other.
(iii) They intersect at the point where x = −1.
(iv) They have different values of y at x = 0.

  • (i), (iii) and (iv)

     

  • (i), (ii), (iii) and (iv)

     

  • (ii) and (iv)

     

  • (i) and (iv)

     

(3)

Here, a?/a? = (1/3)/(1/3) = 1, b?/b? = (−1)/(−1) = 1, c?/c? = 5/(−2).
The two lines are parallel (as a?/a? = b?/b? ≠ c?/c?). Therefore, they do not intersect.

At x = 0, y = (1/3)×0 + 5 = 5.
At x = 0, y = (1/3)×0 − 2 = −2.
Hence, statements (ii) and (iv) are correct

 



Q 8 :    

For the equations 2x + y = 8 and 4x + 2y = 10, select the correct statements:

(i) The lines are identical.
(ii) The lines are parallel.
(iii) The second equation can be reduced to 2x + y = 5.
(iv) There is no solution to this system.

  • (i), (iii) and (iv)

     

  • (i), (ii), (iii) and (iv)

     

  • (ii), (iii) and (iv)

     

  • (i) and (iv)

     

(3)

We have, 2x + y = 8 …(i)
And, 4x + 2y = 10 ⇒ 2(x + y) = 2×5 ⇒ 2x + y = 5.
Here, a?/a? = 2/2 = 1, b?/b? = 1/1 = 1, c?/c? = 8/5.
Since a?/a? = b?/b? ≠ c?/c?, the lines are parallel. So, there is no point of intersection.
Hence, no solution.



Q 9 :    

Given the equations y = −2x + 3 and y = 2x − 1, identify the correct descriptions about their graph and intersection:

(i) The lines intersect in the fourth quadrant.
(ii) The lines intersect in the first quadrant.
(iii) They are parallel lines.
(iv) Area of triangle formed by two lines with y-axis is 2 sq. units.

  • (i), (iii) and (iv)
     

  • (i), (ii), (iii) and (iv)
     

  • (ii) and (iii)
     

  • (ii) and (iv)
     

(4)

Solving the system graphically, they intersect at (1, 1) in the first quadrant.
The lines are not parallel.
Area of ΔABC = (1/2) × AB × PC = (1/2) × 4 × 1 = 2 sq. units.



Q 10 :    

The pair of equations ax + 2y = 9 and 3x + by = 18 represents parallel lines, where a, b are integers, if:

  • a = b

     

  • 3a = 2b
     

     

  • 2a = 3b

     

  • ab = 6

     

(4)

Given, ax + 2y = 9 and 3x + by = 18 represent parallel lines.
∴ a?/a? = b?/b? ≠ c?/c? ⇒ a/3 = 2/b ≠ -9/-18
⇒ a/3 = 2/b ⇒ ab = 6